不能将“int”对象隐式转换为 str？

Question

我正在制作石头剪刀布，当我运行它时，它显示“无法将 'int' 对象隐式转换为 str”。

import time
import random
print("Do you want to play rock, paper, scissors?")
playerscore = 0
cpuscore = 0
game = input()
game = game.upper()
while game == "SURE" or game == "YES" or game == "YEAH": # starts rock                                 paper scissors
    number = random.randint(1, 3)
    if number == 1:
        cpurpors = "SCISSORS"
    elif number == 2:
        cpurpors = "ROCK"
    elif number == 3:
        cpurpors = "PAPER"
    print("Cool! Rock, paper or scissors?")
    rpors = input()
    rpors = rpors.upper()
    print("Rock")
    time.sleep(.5)
    print("Paper")
    time.sleep(.5)
    print("Scissors")
    time.sleep(.5)
    print(cpurpors + "!")
    time.sleep(.5)
    if cpurpors == rpors:
        print("Draw!")
    elif cpurpors == "SCISSORS" and rpors == "PAPER" or cpurpors == "PAPER" and rpors == "ROCK" or cpurpors == "ROCK" and rpors == "SCISSORS":
        cpuscore = cpuscore + 1
        print("Haha, I win!")
    elif rpors == "SCISSORS" and cpurpors == "PAPER" or rpors == "PAPER" and cpurpors == "ROCK" or rpors == "ROCK" and cpurpors == "SCISSORS":
        playerscore = playerscore + 1
        print("Oh no! You win!")
    print("The scores are:")
    print("Guiseppebot: " + cpuscore)
    print(name + ": " + playerscore)
    print("Would you like to play again?")
    game = input()
    game = game.upper()

Answer 1

问题是您将int 变量添加到打印语句中。尝试做这样的事情：

print(name + ": " + str(playerscore))

在该示例中，您将playerscore 设置为string 版本的int。

Answer 2

需要用str 包装整数cpuscore 和playerscore 以将它们转换为字符串，因为它不会隐式执行。

print("Guiseppebot: " + str(cpuscore))
print(name + ": " + str(playerscore))

另一个不错的选择是使用格式，它会为您调用对象上的str，因此您将来不必担心它：

print("Guiseppebot: {}".format(cpuscore))
print("{}: {}".format(name, playerscore))

str 是将非字符串对象转换为字符串的内置函数。它通过调用对象 .__str__ 方法（如果它存在）来实现这一点（并且知道如何处理 int 和 float 等对象。）在此处的文档中阅读更多相关信息 https://docs.python.org/3/library/stdtypes.html#str

Answer 3

我不确定这是否是最好的解决方案，但我的方法是使用 str() 将整数（cpucore）转换为字符串。

import time
import random
name = input ("what's your name? ") #added in input for variable (name)
print("Do you want to play rock, paper, scissors?")
playerscore = 0
cpuscore = 0
game = input()
game = game.upper()
while game == "SURE" or game == "YES" or game == "YEAH": # starts rock                                 paper scissors
    number = random.randint(1, 3)
    if number == 1:
        cpurpors = "SCISSORS"
    elif number == 2:
        cpurpors = "ROCK"
    elif number == 3:
        cpurpors = "PAPER"
    print("Cool! Rock, paper or scissors?")
    rpors = input()
    rpors = rpors.upper()
    print("Rock")
    time.sleep(.5)
    print("Paper")
    time.sleep(.5)
    print("Scissors")
    time.sleep(.5)
    print(cpurpors + "!")
    time.sleep(.5)
    if cpurpors == rpors:
        print("Draw!")
    elif cpurpors == "SCISSORS" and rpors == "PAPER" or cpurpors == "PAPER" and rpors == "ROCK" or cpurpors == "ROCK" and rpors == "SCISSORS":
        cpuscore = cpuscore + 1
        print("Haha, I win!")
    elif rpors == "SCISSORS" and cpurpors == "PAPER" or rpors == "PAPER" and cpurpors == "ROCK" or rpors == "ROCK" and cpurpors == "SCISSORS":
        playerscore = playerscore + 1
        print("Oh no! You win!")
    print("The scores are:")
    print("Guiseppebot: " + str(cpuscore)) #converted cpuscore to a string
    print(name + ": " + str(playerscore)) #variable (name) wasn't declared
    print("Would you like to play again?")
    game = input()
    game = game.upper()

Answer 4

cpuscore 是一个整数(int)，它不能与字符串连接。 Python 不会自动将其转换为字符串（“隐式”）。所以你至少需要做：

print("Guiseppebot: " + str(cpuscore))

更好/更简单，在 Python 3.6+ 中，使用 f-strings 假设您可以将变量中的值放入字符串（整数、字符串、列表、字典都可以），您只需将它们放在大括号内。

下面是带有该错误的行在 f-strings 中的样子：

print(f"Guiseppebot: {cpuscore}")