JSON 与字符串的正确比较 (SWIFT 3)

Question

    request( url!, method: .get, parameters: nil)
        .responseJSON { response in

            print(response.result)   // result of response serialization

            if let newJSON = response.result.value {
                let json = JSON(newJSON)
                for (key,subJson):(String, JSON) in json {

                    let age = subJson["age"]
                    let name = subJson["name"]
                    let status = subJson["status"]

  //the code below looks kind of confusing if it gets longer

                    if age == "22"{
                        if status == "highschool "{
                            if name == "Leo"{
                              //do something with the result 

有没有更好的方法来检查 JSON 的结果是否与字符串相同？

Answer 1

这是经典的pyramid of doom。有几种方法可以摆脱它，您需要根据您的上下文选择合适的方法。基本上方法是：

• 使用提前退货和guard 声明。
• 将多个if-let 语句合并为一个。
• 使用for-where。

鉴于以上所有内容，您可以将您的一段代码重写为如下内容：

request( url!, method: .get, parameters: nil)
    .responseJSON { response in
        print(response.result)   // result of response serialization

        guard let newJSON = response.result.value else { return }

        let json = JSON(newJSON)

        for (key,subJson):(String, JSON) in json {
            let age = subJson["age"]
            let name = subJson["name"]
            let status = subJson["status"]

            if age == "22" && status == "highschool" && name == "Leo" {
                //do something with the result 
            }
        }
    }

Answer 2

两种选择：

if age == "22" && status == "high school " && name == "Leo" {

或

switch (age, status, name) {
    case ("22", "high school ", "Leo"): ...
    ...
    default: ...
}