使用python在S3上上传带有子文件夹和文件的文件夹

Question

我有一个文件夹，其中包含我从服务器获取并分配给变量的一堆子文件夹和文件。文件夹结构如下：

└── main_folder
   ├── folder
    │   ├── folder
    │   │   ├── folder
    │   │   │   └── a.json
    │   │   ├── folder
    │   │   │   ├── folder
    │   │   │   │   └── b.json
    │   │   │   ├── folder
    │   │   │   │   └── c.json
    │   │   │   └── folder
    │   │   │       └── d.json
    │   │   └── folder
    │   │       └── e.json
    │   ├── folder
    │   │   └── f.json
    │   └── folder
    │       └── i.json

现在我想使用 boto3 将此 main_folder 上传到具有相同结构的 S3 存储桶。在 boto3 中，无法在 s3 上上传文件夹。

我在此链接上看到了解决方案，但他们从本地机器获取文件，我从服务器获取数据并分配给变量。

Uploading a folder full of files to a specific folder in Amazon S3

upload a directory to s3 with boto

https://gist.github.com/feelinc/d1f541af4f31d09a2ec3

有人遇到过同样的问题吗？

Answer 1

下面是对我有用的代码，纯 python3。

""" upload one directory from the current working directory to aws """
from pathlib import Path
import os
import glob
import boto3

def upload_dir(localDir, awsInitDir, bucketName, tag, prefix='/'):
    """
    from current working directory, upload a 'localDir' with all its subcontents (files and subdirectories...)
    to a aws bucket
    Parameters
    ----------
    localDir :   localDirectory to be uploaded, with respect to current working directory
    awsInitDir : prefix 'directory' in aws
    bucketName : bucket in aws
    tag :        tag to select files, like *png
                 NOTE: if you use tag it must be given like --tag '*txt', in some quotation marks... for argparse
    prefix :     to remove initial '/' from file names

    Returns
    -------
    None
    """
    s3 = boto3.resource('s3')
    cwd = str(Path.cwd())
    p = Path(os.path.join(Path.cwd(), localDir))
    mydirs = list(p.glob('**'))
    for mydir in mydirs:
        fileNames = glob.glob(os.path.join(mydir, tag))
        fileNames = [f for f in fileNames if not Path(f).is_dir()]
        rows = len(fileNames)
        for i, fileName in enumerate(fileNames):
            fileName = str(fileName).replace(cwd, '')
            if fileName.startswith(prefix):  # only modify the text if it starts with the prefix
                fileName = fileName.replace(prefix, "", 1) # remove one instance of prefix
            print(f"fileName {fileName}")

            awsPath = os.path.join(awsInitDir, str(fileName))
            s3.meta.client.upload_file(fileName, bucketName, awsPath)

if __name__ == '__main__':
    import argparse
    parser = argparse.ArgumentParser()
    parser.add_argument("--localDir", help="which dir to upload to aws")
    parser.add_argument("--bucketName", help="to which bucket to upload in aws")
    parser.add_argument("--awsInitDir", help="to which 'directory' in aws")
    parser.add_argument("--tag", help="some tag to select files, like *png", default='*')
    args = parser.parse_args()

    # cd whatever is above your dir, then run it
    # (below assuming this script is in ~/git/hu-libraries/netRoutines/uploadDir2Aws.py )
    # in the example below you have directory structure ~/Downloads/IO
    # you copy full directory of ~/Downloads/IO to aws bucket markus1 to 'directory' 2020/IO
    # NOTE: if you use tag it must be given like --tag '*txt', in some quotation marks...

    # cd ~/Downloads
    # python ~/git/hu-libraries/netRoutines/uploadDir2Aws.py --localDir IO --bucketName markus1 --awsInitDir 2020
    upload_dir(localDir=args.localDir, bucketName=args.bucketName,
               awsInitDir=args.awsInitDir, tag=args.tag)