ASP.NET FileUpload 文件上传控件

需要在要目录下新建两个目录:upfile和upimg
添加一个FileUpload控件.一个Button.一个Image.一个Label


关键代码:
string name = FileUpload1.FileName;//获得上传文件的名字.
string size = FileUpload1.PostedFile.ContentLength.ToString();//文件大小.
string type = FileUpload1.PostedFile.ContentType;//文件类型.
string type2 = name.Substring(name.LastIndexOf(".") + 1);//LastIndexOf()最后一个索引位置匹配.Substring()里面的+1是重载.
string ipath = Server.MapPath("upimg") + "\\" + name;//取得根目录下面的upimg目录的路径.
string fpath = Server.MapPath("upfile") + "\\" + name;
string wpath = "upimg\\" + name;//获得虚拟路径.
if (type2 == "jpg" || type2 == "gif" || type2 == "bmp" || type2 == "png")
{
FileUpload1.SaveAs(ipath);//保存方法,参数是一个地址字符串.
Image1.ImageUrl = wpath;
Label1.Text = "你传的文件名是:" + name + "<br>文件大小为:" + size + "字节<br>文件类型是:" + type +
"<br>后缀是:" + type2 + "<br>实际路径是:" + ipath + "<br>虚拟路径是:" + fpath;
Image1.Visible = true;
}
else
{
Image1.Visible = false;
FileUpload1.SaveAs(fpath);
Label1.Text = "你传的文件名是:" + name + "<br>文件大小为:" + size + "字节<br>文件类型是:" + type +
"<br>后缀是:" + type2 + "<br>实际路径是:" + ipath + "<br>虚拟路径是:" + fpath;
}