【发布时间】:2019-03-21 08:40:02
【问题描述】:
我想为我的模型创建一个 ListCreateView。 这是模型 -
from django.db import models
from training_service.models.advertiser import Advertiser
class Config(models.Model):
CONFIG_TYPE_CHOICES = (
('DATA_DESCRIPTOR', 'DATA_DESCRIPTOR'),
('DATAFETCH', 'DATAFETCH'),
('BATCHSYSTEM', 'BATCHSYSTEM'),
('SPARKSYSTEM', 'SPARKSYSTEM')
)
id = models.AutoField(primary_key=True)
name = models.CharField(max_length=100)
config_type = models.CharField(max_length=100,
choices=CONFIG_TYPE_CHOICES,
blank=False)
default_value = models.CharField(max_length=1000)
class Meta:
db_table = 'config'
def __unicode__(self):
return str(self.name)
class AdvertiserConfig(models.Model):
advertiser_id = models.ForeignKey(
Advertiser, to_field="advertiser_id", db_column="advertiser_id", on_delete=models.DO_NOTHING)
config_id = models.ForeignKey(Config, on_delete=models.CASCADE)
value = models.CharField(max_length=1000)
class Meta:
db_table = 'advertiser_config'
def __unicode__(self):
return str(self.name)
以下是模型的序列化程序 -
class ConfigSerializer(serializers.ModelSerializer):
class Meta:
model = Config
fields = ('name', 'config_type', 'value_type', 'default_value')
class AdvertiserConfigSerializer(serializers.ModelSerializer):
config_name = serializers.PrimaryKeyRelatedField(read_only=True, many=True)
class Meta:
model = AdvertiserConfig
fields = ('advertiser_id', 'config_name', 'value')
但是当我在 AdvertiserConfig 上执行 get 时,这不起作用我没有在响应中获得 config_name。并且不会抛出任何错误。
知道这里有什么问题吗? 另外,我将如何为 AdvertiserConfig 创建?
【问题讨论】:
标签: python django django-models django-rest-framework python-3.6