尝试从 C# 中的多属性抽象类创建列表答案

【问题标题】：Trying to create a list from a multi-propertied abstract class in C#尝试从 C# 中的多属性抽象类创建列表
【发布时间】：2020-04-16 16:48:51
【问题描述】：

如果我有一个名为 Animal 的抽象类，它具有三个属性（名称、年龄和女性），并且我想在一个名为 Zoo 的类的方法中创建一个动物列表，方法是让列表中的每个实例成为不同的 Animal我该怎么做？到目前为止，以下也是我的代码：

using System;
using System.Collections.Generic;

public abstract class Animal
{
    abstract public string AName();
    abstract public int Age();
    abstract public bool Female();
}

public class Zoo : Animal
{
    public string ZName;
    public string City;
    public int Capacity;
    public List<Animal> Animals = new List<Animal>();

    public Zoo(string name, string city, int capacity)
    {
        ZName = name;
        City = city;
        Capacity = capacity;
    }

    public void addAnimal(Animal animal)
    {
        List<Animal>.Add(animal.Age(), animal.AName(), animal.Female());
    }

这是我必须处理的 UML 图

【问题讨论】：

标签： c# list abstract-class

【解决方案1】：

我认为您正在尝试将抽象 Animal 类用于错误的事情。看起来你正在尝试做一些更像这样的事情：

public class Zoo
{
    public string ZName;
    public string City;
    public int Capacity;
    public List<Animal> Animals = new List<Animal>();

    public Zoo(string name, string city, int capacity)
    {
        ZName = name;
        City = city;
        Capacity = capacity;
    }

    public void addAnimal(Animal animal)
    {
        Animals.Add(animal);
    }
}

public abstract class Animal
{
    public abstract string AName { get; set; }
    public abstract int Age { get; set; }
    public abstract bool Female { get; set; }
}

public class Tiger : Animal
{
    public override string AName { get; set; }
    public override int Age { get; set; }
    public override bool Female { get; set; }
}

public class Lion : Animal
{
    public override string AName { get; set; }
    public override int Age { get; set; }
    public override bool Female { get; set; }
}

我使用上面的类创建了一个小控制台应用程序来演示这个：

    static void Main(string[] args)
    {
        var myZoo = new Zoo("Fun Zoo", "New York", 20);
        myZoo.addAnimal(new Tiger { Age = 10, AName = "Frank", Female = true });
        myZoo.addAnimal(new Lion { Age = 11, AName = "Fred", Female = false });

        Console.WriteLine("Here's the new zoo:");
        Console.WriteLine("Zoo Name: " + myZoo.ZName + ", City: " + myZoo.City + ", Capacity: " + myZoo.Capacity);
        Console.WriteLine();
        Console.WriteLine("Animals at the zoo:");
        foreach (var a in myZoo.Animals)
        {
            Console.WriteLine("Name: " + a.AName + ", Age: " + a.Age + ", Is Female: " + a.Female);
        }

        Console.ReadLine();
    }

结果：

【讨论】：

【解决方案2】：

您不应该将Animal 扩展为Zoo，我认为您想要的更像是：

public class Zoo {
    public string ZName;
    public string City;
    public int Capacity;
    public List<Animal> Animals = new List<Animal>();

    public Zoo(string name, string city, int capacity, List<Animal> animals)
    {
        ZName = name;
        City = city;
        Capacity = capacity;
        Animals = animals
    }

}

并使用已实例化的List 或Animals 初始化动物园

【讨论】：