【发布时间】:2022-01-05 07:08:20
【问题描述】:
但现在我不知道如何过滤
我正在聚合过滤后的数据:
[
{
"_id": "61cea071cfa3c96b9a4d2657",
"name": "Utils",
"children": [
{
"name": "Code",
"_id": "61cebb4e6c4a5c643494d1a1",
"children": [{name:"jahn"}]
},
{
"name": "Image",
"_id": "61ceb8ad6c4a5c643494d11e",
"children": []
}
]
},
{
"_id": "61cea071cfa3c96b9a4d2111",
"name": "Names",
"children": [
{
"name": "que",
"_id": "61cebb4e6c4a5c643494d1a1",
"children": [
]
},
{
"name": "filter",
"_id": "61cebb4e6c4a5c643494d1a1",
"children": [
{name:"jahn"}
]
}
]
},
]
期待您的帮助
子项为空且不显示时如何过滤掉子项
期望的结果:
[
{
"_id": "61cea071cfa3c96b9a4d2657",
"name": "Utils",
"children": [
{
"name": "Code",
"_id": "61cebb4e6c4a5c643494d1a1",
"children": [
{name:"jahn"}
]
}
]
},
{
"children": [
{
"children": [
{name:"jahn"}
]
}
]
},
]
我想要孩子中的孩子,如果它是空的,它不会显示整个对象
【问题讨论】:
-
您好,对于您的场景,您尝试仅在第二级子级为空数组时过滤?
-
我重新编辑了问题以使其更清晰
标签: mongodb mongoose mongodb-query aggregation-framework