XSLT在xml的两个节点之间选择特定的兄弟节点

Question

假设我有以下 XML 结构

<?xml version="1.0" encoding="UTF-8" ?>
<?xml-stylesheet type="text/xsl"?>
<?xml-stylesheet type="text/xsl"?>
<WTT>
<Msg 
    UserText="Iswritable = true" >
</Msg>
<Test 
   BaseLvl="Msg" >
</Test>
<start
   id = "1" >
</start>
<Msg 
   UserText="Iswritable = true" >
</Msg>
<Test 
   BaseLvl="Msg"  >
</Test>
<Msg 
   UserText="WriteBuffers = 2">
</Msg>
<Test 
   BaseLvl="Txt" >
</Test>
<Msg 
   UserText="ReadBuffers = 1">
</Msg>
<end
   id ="1" >
</end>

<start
   id = "2" >
</start>
<Test
   BaseLvl="sound" > 
</Test>
<Test 
   BaseLvl="Msg" >
</Test>
<Msg 
   UserText="vertexbuffers = 1">
</Msg>
<end
   id ="2" >
</end>
<Msg 
   UserText="vertexbuffers = 1">
</Msg>
</WTT>

输出：

<start
   id = "1" >
</start>
<Msg 
   UserText="Iswritable = true" >
</Msg>
<Msg 
   UserText="ReadBuffers = 1">
</Msg>
<end
   id ="1">
</end>
<start
   id = "2" >
</start>
<Msg 
   UserText="vertexbuffers = 1">
</Msg>
<end
   id ="2" >
</end>    

xml的结构不是固定的，任何标签都可以放在任何地方。 有没有办法做到这一点？ 我尝试使用 foreach 并仅选择 msg 节点，但我们无法在 xslt 中破坏 foreach。 我只需要在单独的组中选择<start/> 和<end/> 标记之间的所有<msg/> 标记。

Answer 1

以下样式表：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/WTT">
    <root>
        <xsl:copy-of select="start | end | Msg[preceding-sibling::start[1]/@id = following-sibling::end[1]/@id]"/>
    </root>
</xsl:template>

</xsl:stylesheet>

当应用于您的 XML 输入时，将返回：

<?xml version="1.0" encoding="UTF-8"?>
<root>
   <start id="1"/>
   <Msg UserText="Iswritable = true"/>
   <Msg UserText="WriteBuffers = 2"/>
   <Msg UserText="ReadBuffers = 1"/>
   <end id="1"/>
   <start id="2"/>
   <Msg UserText="vertexbuffers = 1"/>
   <end id="2"/>
</root>