SQL 根据兄弟节点属性值选择 XML 节点

Question

<Findings>
   <Finding EcinRecordID="1042893">
      <Name>Goal Length of Stay for the ORG</Name>
      <Selected Value="0" DisplayValue="No"/>
   </Finding>
   <Finding EcinRecordID="1042894">
      <Name>Goal Length of Stay for the GRG</Name>
      <Selected Value="1" DisplayValue="Yes"/>
      <NoteText>3 days</NoteText>
   </Finding>
</Findings>

2 个挑战：

1. 选择 Findings/Finding/Name 的节点值，其中 Findings/Finding/Selected Value = "1"
2. 选择 Findings/Finding/NoteText 的节点值，其中 Findings/Finding/Selected Value = "1"

把它放到一个存储过程中。我已经使用查询、存在和值尝试了至少 3 打版本。我可以得到 Selected Value = '1'，但似乎无法在 Select 语句中分配相应的 Name 值。

SELECT
   p.value('(Payments[1]/Payment[1]/PreAuthCertNumber)[1]', 'varchar(20)') AS PriorAuthNumber
   ,qa.value('(Name[1])','varchar(255)') AS Question
   ,qa.value('(Findings/Finding/Name)[1]','varchar(255)') AS Answer
    FROM #ValueExample
    CROSS APPLY XMLDocument.nodes('/OutboundDataFeed/Patient/PatientAdmission') as t(p)
    CROSS APPLY XMLDocument.nodes('/OutboundDataFeed/Patient/PatientAdmission/CMAssessments/CMAssessment/Sections/Section/Questions/Question') as u(qa)

谢谢！

Answer 1

declare @XML xml

set @XML = '
<Findings>
   <Finding EcinRecordID="1042893">
      <Name>Goal Length of Stay for the ORG</Name>
      <Selected Value="0" DisplayValue="No"/>
   </Finding>
   <Finding EcinRecordID="1042894">
      <Name>Goal Length of Stay for the GRG</Name>
      <Selected Value="1" DisplayValue="Yes"/>
      <NoteText>3 days</NoteText>
   </Finding>
</Findings>'

select @XML.value('(/Findings/Finding[Selected/@Value = "1"]/Name/text())[1]', 'varchar(255)') as Name,
       @XML.value('(/Findings/Finding[Selected/@Value = "1"]/NoteText/text())[1]', 'varchar(255)') as NoteText

结果：

Name                                     NoteText
---------------------------------------- -------------------------
Goal Length of Stay for the GRG          3 days

Answer 2

仅供参考，当我尝试在我正在使用的 XML 字段的查询中实现此解决方案时，我发现上面 Mikael Eriksson 的答案中提供的语法对我不起作用。结构是正确的，我仔细检查了它的格式是否正确，但我的结果只会得到空值。

提供的语法（摘自 Mikael Eriksson 的回答）是：

select @XML.value('(/Findings/Finding[Selected/@Value = "1"]/Name/text())[1]', 'varchar(255)') as Name,
       @XML.value('(/Findings/Finding[Selected/@Value = "1"]/NoteText/text())[1]', 'varchar(255)') as NoteText

我发现实际上对我有用的是稍微修改它如下（显然，这不是我自己的代码 sn-p，而是为了保持一致性）：

select @XML.value('(/Findings/Finding/Selected[@Value = "1"]/Name/text())[1]', 'varchar(255)') as Name,
       @XML.value('(/Findings/Finding/Selected[@Value = "1"]/NoteText/text())[1]', 'varchar(255)') as NoteText

只是想我会为可能遇到与我相同经历的其他人发帖。