需要从表中的两个不同日期按天计数答案

【问题标题】：Need counts by day from two different dates in a table需要从表中的两个不同日期按天计数
【发布时间】：2015-03-28 03:23:49
【问题描述】：

我觉得这应该是一件容易的事，但我正在为此苦苦挣扎。

我有一个问题表，表中有以下内容：

用户 ID
创建日期
解决日期
问题编号

我两个通过用户 ID 总结了这一点，其中包含在某个日期创建的问题数量和在某个日期解决的问题数量。，

例如，

User ID   ///   Date     ///     Issues Received  ///  Issues Resolved
JonSmith1 ///  1/12/2015 ///            28        ///          34

问题源于我在计算已解决问题时不在乎何时收到问题。因此，已解决计算中的问题可能已在昨天、上周、去年等收到。

任何帮助将不胜感激。

谢谢，体育

【问题讨论】：

收到的问题比解决的问题要少
对于给定的一天，它可以。例如，在 12 日，他们可能会收到总共 28 个问题，但他们在 12 日关闭的前几天的队列中仍有 X 个号码。

标签： mysql sql date join teradata

【解决方案1】：

分别查询这两个日期，然后将它们与UNION 结合起来：

SELECT UserID, Date, MAX(IssuesReceived) AS IssuesReceived, MAX(IssuesResolved) AS IssuesResolved
FROM (
    SELECT UserID, CreatedDate AS Date, COUNT(*) AS IssuesReceived, 0 AS IssuesResolved
    FROM Issues
    GROUP BY UserID, Date
    UNION
    SELECT User, ResolvedDate AS Date, 0 AS IssuesReceived, COUNT(*) AS IssuesResolved
    FROM Issues
    GROUP BY UserID, Date) AS u
GROUP BY UserID

【讨论】：

【解决方案2】：

试试这个。

select userid,createddate as date,
      count(`created date`) as `Issues Received`,
      count(`Resolved Date`) as `Issues Resolved`
from yourtable 
where `Resolved Date` = '1/12/2015'
Group by userid,createddate

考虑到在创建新问题时解决日期将为空

【讨论】：

【解决方案3】：

不确定这是否完全回答了您的问题，但您可能需要像这样进行联合：

select user_id
    , action_date
    , count(case when action = 'CREATED' then 1 else null end)
    , count(case when action = 'RESOLVED' then 1 else null end)
from (
     select user_id, created_date action_date, 'CREATED' action
     from table
     union
     select user_id, resolved_date, 'RESOLVED' action
     from table
     where resolved_date is not null
     ) x
group by user_id, action_date

这行得通吗？

【讨论】：

【解决方案4】：

如果你确实在使用 Teradata，可以使用full outer join：

SELECT COALESCE(i.UserID, r.UserId) as UserId,
       COALESCE(i.Date, r.Date) as Date,
       COALESCE(IssuesReceived, 0) AS IssuesReceived, 
       COALESCE(IssuesResolved, 0) AS IssuesResolved
FROM (SELECT UserID, CreatedDate AS Date, COUNT(*) AS IssuesReceived
      FROM Issues
      GROUP BY UserID, Date
     ) i FULL OUTER JOIN
     (SELECT User, ResolvedDate AS Date, COUNT(*) AS IssuesResolved
      FROM Issues
      GROUP BY UserID, Date
     ) r
     ON i.UserId = r.UserId and i.Date = r.Date;

【讨论】：