【问题标题】:How to fix "TypeError" in Holt and Holt-Winters function of statsmodels in Python如何修复 Python 中 statsmodels 的 Holt 和 Holt-Winters 函数中的“TypeError”
【发布时间】:2019-03-26 06:17:39
【问题描述】:

我使用这样的数据

data = [253993,275396.2,315229.5,356949.6,400158.2,442431.7,495102.9,570164.8,\
640993.1,704250.4,767455.4,781807.8,776332.3,794161.7,834177.7,931651.5,\
1028390,1114914]

然后,我导入 statsmodels 并使用 Holt 方法

import matplotlib.pyplot as plt
from statsmodels.tsa.holtwinters import ExponentialSmoothing, SimpleExpSmoothing, Holt

# Holt’s Method
fit1 = Holt(data).fit(smoothing_level=0.8, smoothing_slope=0.2, optimized=False)
l1, = plt.plot(list(fit1.fittedvalues) + list(fit1.forecast(5)), marker='o')

fit2 = Holt(data, exponential=True).fit(smoothing_level=0.8, smoothing_slope=0.2, optimized=False)
l2, = plt.plot(list(fit2.fittedvalues) + list(fit2.forecast(5)), marker='o')

fit3 = Holt(data, damped=True).fit(smoothing_level=0.8, smoothing_slope=0.2)
l3, = plt.plot(list(fit3.fittedvalues) + list(fit3.forecast(5)), marker='o')

l4, = plt.plot(data, marker='o')
plt.legend(handles = [l1, l2, l3, l4], labels = ["Holt's linear trend", "Exponential trend", "Additive damped trend", 'data'], loc = 'best', prop={'size': 7})
plt.show()

fit2 中抛出异常

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-17-9ce7957db4db> in <module>()
      3 l1, = plt.plot(list(fit1.fittedvalues) + list(fit1.forecast(5)), marker='o')
      4 
----> 5 fit2 = Holt(data, exponential=True)
      6 fit2.fit(smoothing_level=0.8, smoothing_slope=0.2, optimized=False)
      7 l2, = plt.plot(list(fit2.fittedvalues) + list(fit2.forecast(5)), marker='o')

g:\competition\venv\lib\site-packages\statsmodels\tsa\holtwinters.py in __init__(self, endog, exponential, damped)
    851     def __init__(self, endog, exponential=False, damped=False):
    852         trend = 'mul' if exponential else 'add'
--> 853         super(Holt, self).__init__(endog, trend=trend, damped=damped)
    854 
    855     def fit(self, smoothing_level=None, smoothing_slope=None, damping_slope=None, optimized=True):

g:\competition\venv\lib\site-packages\statsmodels\tsa\holtwinters.py in __init__(self, endog, trend, damped, seasonal, seasonal_periods, dates, freq, missing)
    389         self.trending = trend in ['mul', 'add']
    390         self.seasoning = seasonal in ['mul', 'add']
--> 391         if (self.trend == 'mul' or self.seasonal == 'mul') and (endog <= 0.0).any():
    392             raise NotImplementedError(
    393                 'Unable to correct for negative or zero values')

TypeError: '<=' not supported between instances of 'list' and 'float'

不知道为什么,其他都正常。(Holt-Winters法也是这样)

我认为是指数参数导致了问题。那么我应该怎么做才能使用指数模型呢?

【问题讨论】:

    标签: python statsmodels holtwinters


    【解决方案1】:

    我对这个库不是很有经验,但它似乎想要一个系列而不是数据列表。引入 pandas.pd 并将您的数据转换为 pd.Series:

    import matplotlib.pyplot as plt
    from statsmodels.tsa.holtwinters import ExponentialSmoothing, SimpleExpSmoothing, Holt
    import pandas as pd
    
    data = [253993,275396.2,315229.5,356949.6,400158.2,442431.7,495102.9,570164.8,\
    640993.1,704250.4,767455.4,781807.8,776332.3,794161.7,834177.7,931651.5,\
    1028390,1114914]
    
    series = pd.Series(data)
    
    # Holt's Method
    fit1 = Holt(series).fit(smoothing_level=0.8, smoothing_slope=0.2, optimized=False)
    l1, = plt.plot(list(fit1.fittedvalues) + list(fit1.forecast(5)), marker='o')
    
    fit2 = Holt(series, exponential=True).fit(smoothing_level=0.8, smoothing_slope=0.2, optimized=False)
    l2, = plt.plot(list(fit2.fittedvalues) + list(fit2.forecast(5)), marker='o')
    
    fit3 = Holt(series, damped=True).fit(smoothing_level=0.8, smoothing_slope=0.2)
    l3, = plt.plot(list(fit3.fittedvalues) + list(fit3.forecast(5)), marker='o')
    
    l4, = plt.plot(series, marker='o')
    plt.legend(handles = [l1, l2, l3, l4], labels = ["Holt's linear trend", "Exponential trend", "Additive damped trend", 'data'], loc = 'best', prop={'size': 7})
    plt.show()
    

    【讨论】:

    • 您是否愿意接受答案之类的,以便我获得积分?
    • 对不起,我才看到。谢谢。
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