paginate_queryset() 有一个意外的关键字参数“视图”答案

【问题标题】：paginate_queryset() got an unexpected keyword argument 'view'paginate_queryset() 有一个意外的关键字参数“视图”
【发布时间】：2021-04-15 08:20:30
【问题描述】：

在运行以下代码时，添加分页后出现“paginate_queryset() 出现意外的关键字参数 'view'”错误

views.py

class UsersList(ListAPIView,LimitOffsetPagination):
    permission_classes = (permissions.IsAuthenticated, IsVerified,permissions.IsAdminUser)


    @swagger_auto_schema(
        query_serializer=PaginationSerializer,
        responses={status.HTTP_200_OK: UserOutputSerializer(many=True)},
        operation_id="list_users",
    )
    def get(self, request, *args, **kwargs):
        qs = User.objects.filter(is_verified=True, is_active=True).order_by('user_name')
        results = self.paginate_queryset(qs, request, view=self)
        users = UserOutputSerializer(results, many=True)
        return self.get_paginated_response(users.data)

urls.py

path('list_users/',UsersList.as_view(),name='list_users'),

【问题讨论】：

您到底想在视图中传递什么？

标签： python python-3.x django django-rest-framework django-views

【解决方案1】：

通过重写 get 这样的方法，您正在丢弃有关 ListAPIView 的所有好东西。如果你想用户swagger_auto_schema，那么试试这样：

class UsersList(ListAPIView,LimitOffsetPagination):
    permission_classes = (permissions.IsAuthenticated, IsVerified,permissions.IsAdminUser)
    serializer_class = UserOutputSerializer
    paginate_by = 10
    queryset = User.objects.filter(is_verified=True, is_active=True).order_by('user_name')
   
    @swagger_auto_schema(
        query_serializer=PaginationSerializer,
        responses={status.HTTP_200_OK: UserOutputSerializer(many=True)},
        operation_id="list_users",
    )
    def get(self, request, *args, **kwargs):
        return super().get(request, *args, **kwargs)

【讨论】：