在 cursor.execute() 中的 sql 查询中传递多个参数答案

【问题标题】：Passing multiple parameters in sql query in cursor.execute()在 cursor.execute() 中的 sql 查询中传递多个参数
【发布时间】：2017-11-07 13:20:04
【问题描述】：

我正在尝试将多个参数传递给 sql 查询，但它给我带来了错误，

这里是查询

cbd_id=[1,10,19,31,37,42,48,57,63,64,65]


cursor.execute('''select t1.id as pid,pxval,pyval from <tbl1> t1 left join (select * from <tbl2> where clubid=? t2 on t1.id=t2.projectid where t1.cityid in (SELECT cityid FROM <tbl3> WHERE cbdid =? group by cityid) and t1.pxval>0 and t2.distance is null order by projectid)''',(cbd_id[i],cbd_id[i]))

它给了我错误

ProgrammingError: ('42000', "[42000] [Microsoft][ODBC SQL Server Driver][SQL Server]Incorrect syntax near 't2'. (102) (SQLExecDirectW)")

但是我查了没发现问题，

对此的任何建议都会有所帮助。

谢谢

【问题讨论】：

您可能在某处遗漏了右括号。一个示例是在 t2 别名之前缺少的那个。应该是select t1.id as pid,pxval,pyval from <tbl1> t1 left join (select * from <tbl2> where clubid=?) t2。

标签： python sql sql-server pyodbc

【解决方案1】：

正如错误消息所示，您的 SQL 命令文本格式不正确。为了清楚起见，重新格式化，您的查询是

select t1.id as pid,pxval,pyval 
from 
    <tbl1> t1 
    left join 
    (
        select * 
        from <tbl2> 
        where clubid=? 
    t2 
        on t1.id=t2.projectid 
where 
    t1.cityid in (
            SELECT cityid 
            FROM <tbl3> 
            WHERE cbdid =? 
            group by cityid) 
    and 
    t1.pxval>0 
    and 
    t2.distance is null 
order by projectid)

注意<tbl2> 子查询没有右括号。您的查询可能应该是

select t1.id as pid,pxval,pyval 
from 
    <tbl1> t1 
    left join 
    (
        select * 
        from <tbl2> 
        where clubid=? 
    ) t2 
        on t1.id=t2.projectid 
where 
    t1.cityid in (
            SELECT cityid 
            FROM <tbl3> 
            WHERE cbdid =? 
            group by cityid) 
    and 
    t1.pxval>0 
    and 
    t2.distance is null 
order by projectid

【讨论】：