获取总和小于或等于数据集中值的记录

Question

这个问题是这里问题Query to get all records until the sum of column less than or equal a value的延伸

对于表格：项目

slno	item	price
1	item1	1000
2	item2	2000
3	item3	3000
4	item4	4000
5	item5	5000
6	item6	6000

表格：值

id	value
1	3500
2	6000
3	10000
4	21000

获取总和（价格）等于或小于表值中每个数字的项目中的所有记录

结果是

id	item
1	item1
1	item2
2	item1
2	item2
2	item3
3	item1
3	item2
3	item3
3	item4
4	item1
4	item2
4	item3
4	item4
4	item5
4	item6

SELECT slno, item, price
  FROM
(
  SELECT slno, item, price, 
  (
    SELECT SUM(price)
      FROM table1
     WHERE slno <= t.slno
  ) total
    FROM table1 t
) q
 WHERE total <= 10000
 ORDER BY slno

以上解决方案适用于单个值 10000 此解决方案由 https://stackoverflow.com/users/1920232/peterm 提供

如何获取表中每个值的记录：值

Answer 1

使用累积和然后join：

select v.*, i.*
from (select i.*, sum(price) over (order by slno) as running_price
      from items i
     ) i join
     values v
     on i.running_price <= v.value
order by v.id, i.slno;