连接字符串时插入逗号的问题答案

【问题标题】：Issue in inserting comma while concatenating strings连接字符串时插入逗号的问题
【发布时间】：2013-07-22 07:09:52
【问题描述】：

在我的应用程序中，我有一个 address 标签，其中包含 "address1"、"Address2"、" 的值城市” 和 “州”。在标签中显示时，我需要在每个值之间插入逗号。

但如果一个字符串没有值（比如 "Address2"），则不应在其中插入唯一的逗号。

谁能帮我解决这个问题？

【问题讨论】：

这些字段是必填的还是都是可选的？
接受的这个问题的答案是你想要的：stackoverflow.com/questions/14366431/nsstring-from-nsarray
@Manoj：使用 NSMutableString。参考这个链接：developer.apple.com/library/ios/#documentation/Cocoa/Reference/…
@OP：这是一个简单的算法。您只需做您需要的事情。您浏览各个字段，将其连接到结果字符串，仅在当前字段不为空时插入逗号。这有什么难的？
你的地址1、地址2、城市、州和其他人在字典里吗？

标签： iphone ios nsstring uilabel

【解决方案1】：

这里认为dictLocation 是一个字典，其中包含 Address1、Address2、City、State、Country 和 Zip：

示例dictLocation:

NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:@"add1", @"Address1", @"add2", @"Address2",@"cityname",@"City",@"state",@"StateName",@"country",@"CountryName",@"350010",@"ZipCode",nil];

代码：

-(NSMutableString *)createLocationAddress:(NSDictionary *)dictLocation
{
    NSMutableString *strAddress = [[NSMutableString alloc] initWithString:@""];

    NSString *strStreetAddress1 = @"";
    if(dictLocation != nil && [dictLocation valueForKey:@"Address1"] != nil)
    {
        strStreetAddress1 = [StringUtility trimWhiteSpaceAndNewLine:[dictLocation valueForKey:@"Address1"]];
    }

    [strAddress appendString:strStreetAddress1];


    NSString *strAddress2 = @"";
    if(dictLocation != nil && [dictLocation valueForKey:@"Address2"] != nil)
    {
        strAddress2 = [StringUtility trimWhiteSpaceAndNewLine:[dictLocation valueForKey:@"Address2"]];
    }

    if(![strAddress2 isEqualToString:@""])
    {
        if(![strAddress isEqualToString:@""])
            [strAddress appendString:@", "];
        [strAddress appendString:strAddress2];
    }


    NSString *strLocationCity = @"";
    if(dictLocation != nil && [dictLocation valueForKey:@"City"] != nil)
    {
        strLocationCity = [StringUtility trimWhiteSpaceAndNewLine:[dictLocation valueForKey:@"City"]];
    }

    if(![strLocationCity isEqualToString:@""])
    {
        if(![strAddress isEqualToString:@""])
            [strAddress appendString:@", "];
        [strAddress appendString:strLocationCity];
    }

    NSString *strLocationState = @"";
    if(dictLocation != nil && [dictLocation valueForKey:@"StateName"] != nil)
    {
        strLocationState = [StringUtility trimWhiteSpaceAndNewLine:[dictLocation valueForKey:@"StateName"]];
    }

    if(![strLocationState isEqualToString:@""])
    {
        if(![strAddress isEqualToString:@""])
            [strAddress appendString:@",\n"];
        [strAddress appendString:strLocationState];
    }

    NSString *strLocationCountry = @"";
    if(dictLocation != nil && [dictLocation valueForKey:@"CountryName"] !=nil)
    {
        strLocationCountry = [StringUtility trimWhiteSpaceAndNewLine:[dictLocation valueForKey:@"CountryName"]];
    }

    if(![strLocationCountry isEqualToString:@""])
    {
        if(![strAddress isEqualToString:@""])
            [strAddress appendString:@", "];
        [strAddress appendString:strLocationCountry];
    }

    NSString *strLocationZipcode = @"";
    if(dictLocation != nil && [dictLocation valueForKey:@"ZipCode"] != nil)
    {
        strLocationZipcode = [StringUtility trimWhiteSpaceAndNewLine:[dictLocation valueForKey:@"ZipCode"]];
    }

    if(![strLocationZipcode isEqualToString:@""])
    {
        if(![strAddress isEqualToString:@""])
            [strAddress appendString:@", "];
        [strAddress appendString:strLocationZipcode];
    }

    return strAddress;

}

希望这会有所帮助。

如果您还需要什么，请告诉我

【讨论】：