基于列中标准的百分比

Question

我想弄清楚如何在下表底部获得百分比行。

SD    a    b     c        d       e
D   2168 1545   2163    1540    2153
S   435   212   410      193    391
T   13208 5438  12935   5337    12656

我想将 D 行和 S 行除以 T 行来创建两个新的百分比行。这可能吗？ 输出如下所示：

 SD   a       b      c        d       e
D   2168    1545    2163    1540    2153
S   435      212    410      193    391
T   13208    5438   12935   5337    12656
D/T 0.164    0.284  0.167   0.288   0.170
S/T 0.033    0.04   0.032   0.04    0.031

我只需要百分比，所以不一定需要在表格中，但如果是的话，那也没关系。

TIA。

Answer 1

这很麻烦，但它可以用你的表名替换#temp

select *, row_number() over (order by SD)rownum into #temp2 from #temp 


select *from #temp2   
union
select 'D/T',(select a from #temp2 where sd='D')/ cast((select a from #temp2 where sd='T')  as float),
 (select b from #temp2 where sd='D')/ cast((select b from #temp2 where sd='T')  as float),
  (select c from #temp2 where sd='D')/ cast((select c from #temp2 where sd='T')  as float),
 (select d from #temp2 where sd='D')/ cast((select d from #temp2 where sd='T')  as float),
 (select e from #temp2 where sd='D')/ cast((select e from #temp2 where sd='T')  as float), 
 (select max(rownum)+1 from #temp2)
 union
select 'S/T',(select a from #temp2 where sd='S')/ cast((select a from #temp2 where sd='T')  as float),
 (select b from #temp2 where sd='S')/ cast((select b from #temp2 where sd='T')  as float),
  (select c from #temp2 where sd='S')/ cast((select c from #temp2 where sd='T')  as float),
 (select d from #temp2 where sd='S')/ cast((select d from #temp2 where sd='T')  as float),
 (select e from #temp2 where sd='S')/ cast((select e from #temp2 where sd='T')  as float), 
 (select max(rownum)+2 from #temp2)
 order by rownum

Answer 2

你可以这样做：

select t.sd, t.a, t.b, t.c, t.d, t.e
from t
union all
select sd.sd + '/T', sd.a * 1.0 / t.a, sd.b * 1.0 / t.b, sd.c * 1.0 / t.c,
       sd.d * 1.0 / t.d, sd.e * 1.0 / t.d
from t sd cross join
     (select t2.* from t t2 where sd = 'T') tt
where sd in ('D', 'S');

虽然实际上这会按您想要的顺序返回行，但这并不能保证。另请注意，最后的列都将具有相同的类型。