【发布时间】：2019-01-20 08:23:45
【问题描述】：
我正在尝试为我的 C 类编写一个程序来跟踪银行存款。它为您提供了一个菜单，其中包含输入存款的选项、显示所有存款的总和、从最高到最低的存款（使用冒泡排序）、显示平均存款、显示最低存款，然后是退出选项.据我所知，输入、总和和退出选项工作得很好，但其他三个选项都坏了。当你选择它们时，无论你对数组做了什么输入，它的作用就像它们都等于零。这是我到目前为止所拥有的：
#include <stdlib.h>
#include <stdio.h>
int main()
{
int sortCount, sortCount2, sortCount3, swap;// variables for sort
int depositCount = 0, sumCount, lowestCount;
int averageCount, avgSum = 0, avg; //variables for average
char switchInput = 0;//menu input
double deposits[100] = { 0 }, sum = 0, average;
do
{
printf("BANKING MAIN MENU\n\n");
printf("[M]ake a new deposit\n");
printf("[S]um of all deposits\n");
printf("[D]eposits will be displayed from highest to lowest\n");
printf("[A]verage of all deposits\n");
printf("[L]owest deposit will be displayed\n");
printf("[Q]uit\n\n");
printf("Please enter selection:\n\n");
scanf(" %c", &switchInput);
switch (switchInput)
{
case 'm': case 'M'://Deposit screen
printf("\nPlease enter deposit:\n\n");
scanf("%lf", &deposits[depositCount++]);//deposit input
;
for (sortCount = 0; sortCount < depositCount; sortCount++)//Should sort the array highest to lowest
for (sortCount2 = 0; sortCount2 < depositCount - sortCount - 1; sortCount2++)
if (deposits[sortCount] < deposits[sortCount+1])
{
swap = deposits[sortCount];
deposits[sortCount] = deposits[sortCount+1];
deposits[sortCount+1] = swap;
}
break;
case 's': case 'S'://Total of deposits screen
for (sumCount = 0; sumCount < depositCount; sumCount++)//depositCount should have it only use parts of the array where there are inputs.
sum = sum + deposits[sumCount];
printf("\nYour total deposits equal $%.2lf\n\n", sum);
break;
case 'd': case 'D'://Highest to lowest screen
for (sortCount3 = 0; sortCount3 < depositCount; sortCount3++)//depositCount should have it only use parts of the array where there are inputs.
{
printf("$%d \n", deposits[sortCount3]);
}
break;
case 'a': case 'A'://Average screen
for (sumCount = 0; sumCount < depositCount; sumCount++) //depositCount should have it only use parts of the array where there are inputs.
{
avgSum = avgSum + deposits[sumCount];
avg = avgSum / depositCount;
}
printf("Your average deposit is $%.2lf.\n", avg);
break;
case 'l': case 'L'://Lowest screen
printf("The lowest deposit is $%.2lf.\n", deposits[depositCount]);//If the numbers are ordered from highest to lowest, the then entry in the array at the position equal to the number of deposits should be the lowest
break;
case 'q': case 'Q'://quit screen
printf("\nThank you for using our bank!\n\n");
system("pause");
return 0;
break;
default ://invalid option
printf("\nInvalid selection!\n\n");
}
} while (switchInput != 'q'||'Q');
}
【问题讨论】：
-
贴出的代码编译不干净！编译时，始终启用警告，然后修复这些警告。 （对于
gcc，至少使用：-Wall -Wextra -Wcnversion -pedantic -std=gnu11）注意：其他编译器使用不同的选项来产生相同的结果 -
关于：
} while (switchInput != 'q'||'Q');在 C 中，一次只能检查一件事。所以最好写成：} while (switchInput != 'q'|| switchInput == 'Q');更好的方法是使用头文件中的tolower()；ctype.h然后写：} while ( tolower( switchInput ) != 'q' );); -
冒泡排序不适用于
for-loops。请谷歌“冒泡排序”。 -
@PaulOgilvie 你是什么意思？冒泡排序基本上是一个 for 嵌套在另一个
-
@user3629249 必须是
} while (switchInput != 'q' && switchInput != 'Q');^^
标签： c arrays switch-statement average bubble-sort