SQL 从 2 个表中添加值答案

【问题标题】：SQL Add Values from 2 TablesSQL 从 2 个表中添加值
【发布时间】：2013-09-30 17:06:19
【问题描述】：

我需要从两个表中添加 uniqueid 和 WBid。通过下面的输入，我从两个表中都得到了正确的数据，但它只是按行列出，而不是求和。

select distinct COUNT(l.uniqueid), SUM(r.WBid), l.uniqueid, l.firstname, ``l.lastname,       l.email, l.phone, l.mobile, l.address, l.city  FROM EDW..lookupuser l 
INNER JOIN DB..DimBD b on b.userid = l.userId
INNER JOIN DB..FactVP v on v.BidderId = b.bidderid
INNER JOIN DB..FactRD r on r.buyerid = b.bidderid
and r.AuctionDate > '2012-12-31'
GROUP BY l.uniqueid, l.email, l.phone, l.mobile, l.address, l.city, l.firstname, l.lastname

UNION 
select distinct COUNT(l.uniqueid), SUM(t.WBid), l.uniqueid, l.firstname, l.lastname,     l.email, l.phone, l.mobile, l.address, l.city  FROM EDW..lookupuser l
INNER JOIN DB..DimB b on b.userid = l.userId
INNER JOIN DB..FactVP v on v.BidderId = b.bidderid
INNER JOIN DB..FactTA t on t.BidderId = b.bidderid
and t.AuctionDate > '2012-12-31'
GROUP BY l.uniqueid, l.email, l.phone, l.mobile, l.address, l.city, l.firstname, l.lastname
order by l.email asc

【问题讨论】：

标签： sql sum union add

【解决方案1】：

您必须先进行联合，然后他们对其求和。否则你会得到两组结果：

SELECT DISTINCT COUNT(uniqueid), SUM(WBid), uniqueid, firstname, lastname, email, phone, mobile, address, city
FROM (
   SELECT l.uniqueid, r.WBid, l.uniqueid, l.firstname, ``l.lastname, l.email, l.phone, l.mobile, l.address, l.city
   FROM EDW..lookupuser l
   INNER JOIN DB..DimBD b ON b.userid = l.userId
   INNER JOIN DB..FactVP v ON v.BidderId = b.bidderid
   INNER JOIN DB..FactRD r ON r.buyerid = b.bidderid AND r.AuctionDate > '2012-12-31'

   UNION

   SELECT l.uniqueid, t.WBid, l.uniqueid, l.firstname, l.lastname, l.email, l.phone, l.mobile, l.address, l.city
   FROM EDW..lookupuser l
   INNER JOIN DB..DimB b ON b.userid = l.userId
   INNER JOIN DB..FactVP v ON v.BidderId = b.bidderid
   INNER JOIN DB..FactTA t ON t.BidderId = b.bidderid AND t.AuctionDate > '2012-12-31'
   ) x
GROUP BY uniqueid, email, phone, mobile, address, city, firstname, lastname
ORDER BY email ASC

【讨论】：