将 sql 数据（2 个表）从数据库添加到网页

Question

我正在尝试将两个表中的数据添加到我的 PHP 网站。数据应采用表格布局。表“自行车”正在使用制造商表中的 ID

<?php
    echo '<table>';
    echo '<thead>';
    echo '<tr>';
    echo '<th>Model</th>';
    echo '<th>condition</th>';
    echo '<th style="width: 10%">Price</th>';
    echo '<th style="width: 5%">&nbsp;</th>';
    echo '<th style="width: 5%">&nbsp;</th>';
    echo '</tr>';

    $products = $pdo->query('SELECT * FROM bikes');

    foreach ($products as $product) {
        echo '<tr>';
        echo '<td>' . $product['model'] . '</td>';
        echo '<td>' . $product['condition'] . '</td>';
        echo '<td>£' . $product['price'] . '</td>';
        echo '<td><a style="float: right" href="editbike.php?id=' . $product['id'] . '">Edit</a></td>';
        echo '<td><form method="post" action="deletebike.php">
        <input type="hidden" name="bikeId" value="' . $product['id'] . '" />
        <input type="submit" name="submit" value="Delete" />
        </form></td>';
        echo '</tr>';
    }

    echo '</thead>';
    echo '</table>';

    }

    else {
?>

另一个表称为制造商...有没有办法可以将制造商表中的数据添加到网站中，并且数据彼此相邻列出，因为这看起来像表格布局？ （如果不确定我的意思，请添加我正在尝试做的电子邮件和不良电子邮件屏幕截图）

Answer 1

您需要在 2 个表之间创建关系，例如将manufacturer_id 添加到bikes 表中。

然后您可以简单地在两个表中进行选择：

$products = $pdo->query('SELECT b.*, m.* FROM bikes AS b, manufacturers AS m WHERE m.id = b.manufacturer_id');

或use a join:

$products = $pdo->query('SELECT b.*, m.* FROM bikes AS b JOIN manufacturers AS m ON m.id = b.manufacturer_id');

如果这些表共享列名，例如“名称”，那么您需要为其中之一设置别名：

$products = $pdo->query('SELECT b.*, m.*, m.name AS manufacturer_name FROM bikes AS b JOIN manufacturers AS m ON m.id = b.manufacturer_id');

$products['name'] = 'bike name';
$products['manufacturer_name'] = 'manufacturer name';

只要两列名称相同，第一个选择将优先，在上述情况下，bikes 将优先，如果您反转选择，制造商将优先：

$products = $pdo->query('SELECT m.*, b.*, m.name AS manufacturer_name FROM bikes AS b JOIN manufacturers AS m ON m.id = b.manufacturer_id');

$products['name'] = 'manufacturer name';
$products['manufacturer_name'] = 'manufacturer name';