【发布时间】:2014-12-11 17:50:10
【问题描述】:
这个错误是什么意思?我怎样才能摆脱这个问题?
Traceback (most recent call last):
File "bestcodeever.py", line 16, in <module>
html=urllib2.urlopen('http://' + fulllink).read()
File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 410, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 523, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 448, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 531, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 503: Service Unavailable
【问题讨论】:
-
"Service Unavailable" 的哪一部分让您感到困惑?我们是否应该猜测您要连接到哪个网站?
-
服务不可用时通常会出现“服务不可用”错误。我建议等到服务可用后再试。
标签: python-2.7 web-scraping web-crawler urllib2 python-requests