使用 ARM/C 复制字符串

Question

所以我正在尝试学习 ARM，并通过从 C 中获取字符数组指针、复制该字符串并返回指向不同字符数组的指针来练习。我已经编写了这段代码（注释了我假设我发生的事情）：

    .global copy                    @Let the linker know what's going on

copy:                           @Start
    stmfd sp!, {v1-v6, lr}      @Push stuff onto stack
    mov r6, a1                  @Put the pointer to the original string in r6
    bl length                   @Get the length of the string
    mov a1, r4                  @Put length into the input parameter
    bl malloc                   @Allocate enough memory for our new string
    mov r9, a1                  @Move the first memory location to r9

loop:                           @Loop to copy string
    ldrb r8, [r6], #1           @Load first character from string and move pointer
    strb r8, [a1], #1           @Store character in new string and move character
    subs r4, r4, #1             @Subtract 1 from length
    bne loop                    @Stop looping if string is done
    mov a1, r9                  @Move the start of the new string to the return value
    b ending                    @Go to the ending


length:                         @Length function
    mov r4, #0                  @counter set to 0
countLoop: 
    ldrb r5, [r6], #1           @Load first character
    cmp r5, #0                  @Check for null character
    add r4, r4, #1              @Add 1 to the length
    bne countLoop               @Loop if we're not at the end
    mov pc, lr                  @Return the program

ending:
    ldmfd sp!, {v1-v6, pc}      @Pop stuff off the stack
.end

使用这个 C 驱动程序：

#include <stdlib.h>
extern char * copy( char str[] ) ; /* declare the assembly routine */
int main( int argc, char * argv[] )
{
   char str[] = "abcd" ;
   char * result;
   result = copy( str ) ; /* call the assembly language routine */
   printf("Will this work? %s", result);
   exit(0);
}

但是我一直得到结果（null）。显然我的想法有些不对劲，但我不知道它是什么。任何帮助，将不胜感激！

Answer 1

您在开始时将指向原始字符串的指针移动到 r6，但之后您立即在 length 函数中覆盖了 r6。我建议要么将它存储在其他地方，要么直接在该函数调用中使用 a1

Answer 2

'length函数有问题。

1. 使用错误结果的退出比较
2. 结果不允许尾随 NUL 字符
3. 指向原始字符串的指针未递增

建议：

length:                         @Length function
    mov r4, #1                  @Init counter (always have trailing null)
    mov r5, r6                  @Load ptr to first character

lengthLoop: 
    cmp [r5], #0                @Check for null character
    beq lengthEnd               @done

    add r4, r4, #1              @Add 1 to the length
    add r5, r5, #1              @step to next char in source
    b   lengthLoop              @Loop

lengthEnd:
    mov pc, lr                  @return via link register