【发布时间】:2021-07-14 14:08:03
【问题描述】:
我正在尝试创建一个对两个变量中缺失/缺失值是否重叠进行交叉制表的函数。
该函数采用两个变量和数据集。它看起来像这样:
absent_2by2 <- function(var1, var2, data){
require(tidyverse)
require(gtsummary)
require(data.table)
data %>%
as.data.table() %>%
mutate(var1_c = 0) %>%
.[!is.na(var1), var1_c := 1] %>%
.[is.na(var1), var1_c := 2] %>%
mutate(var1_c = as.factor(var1_c),
var1_c = fct_recode(var1_c,
"Present" = "1",
"Absent" = "2")
) %>%
mutate(var2_c = 0) %>%
.[!is.na(var2), var2_c := 1] %>%
.[is.na(var2), var2_c := 2] %>%
mutate(var2_c = as.factor(var2_c),
var2_c = fct_recode(var2_c,
"Present" = "1",
"Absent" = "2")
) %>%
gtsummary::tbl_cross(data,
var2_c, var1_c,
percent = "no")
}
当我使用以下代码调用函数时:
absent_2by2("Ozone", "Solar.R", airquality)
...输出如下所示:
...这是我得到的错误:
Warning messages:
1: Problem with `mutate()` column `var1_c`.
ℹ `var1_c = fct_recode(var1_c, Present = "1", Absent = "2")`.
ℹ Unknown levels in `f`: 2
2: Problem with `mutate()` column `var2_c`.
ℹ `var2_c = fct_recode(var2_c, Present = "1", Absent = "2")`.
ℹ Unknown levels in `f`: 2
该函数似乎没有获取我的两个变量的第 2 级。不知道为什么会这样,因为当我将代码作为一个管道串在一起时,我得到了正确的输出。独立代码如下所示:
require(tidyverse)
require(gtsummary)
require(data.table)
airquality %>%
as.data.table() %>%
mutate(var1_c = 0) %>%
.[!is.na(Ozone), var1_c := 1] %>%
.[is.na(Ozone), var1_c := 2] %>%
mutate(var1_c = as.factor(var1_c),
var1_c = fct_recode(var1_c,
"Present" = "1",
"Absent" = "2")
) %>%
mutate(var2_c = 0) %>%
.[!is.na(Solar.R), var2_c := 1] %>%
.[is.na(Solar.R), var2_c := 2] %>%
mutate(var2_c = as.factor(var2_c),
var2_c = fct_recode(var2_c,
"Present" = "1",
"Absent" = "2")
) %>%
gtsummary::tbl_cross(.,
var2_c, var1_c,
percent = "no"
)
输出如下所示:
如果有人可以指导我,我将不胜感激。谢谢!
【问题讨论】:
标签: r function dplyr gtsummary