【发布时间】:2015-11-25 13:44:32
【问题描述】:
我编写了一个函数来加载空间数据,从输入数据集中提取数据并将该数据集与空间数据合并。然后我的函数返回一个地图,我的案例被绘制在该地图上。
如果我按以下方式返回我的绘图,我的函数可以正常工作: (填充 = totalCases)
return ({
ggplot() +
geom_polygon(data = sl_adm2_Month, aes(x = long, y = lat, group = group,
fill = totalCases), colour = "white") +
geom_text(data = sl_adm2_months_names_DF, aes(label = NAME_2, x = long.1, y = lat.2, group = NAME_2), size = 3) +
# labs(title = paste("Ebola", str_sub(as.character(variable), 6, -1), "cases by district in Sierra Leone - until", format(as.Date(date), "%B %Y"))) +
xlab("") +
ylab("") +
theme_gray() +
theme(legend.position = "bottom")
})
但是,我的目标是传递一个参数,为填充参数提供值(= 变量),正如您在下面的代码中看到的那样。但这会引发以下错误:
eval(expr, envir, enclos) 中的错误:找不到对象“变量”
这是我的代码:
plotMonths <- function(data, variable, date) {
# Reloading district polygons
sl_adm2_months <- readOGR("C:/Users/woba/Documents/Ordina/TFS-Projects/Ordina - Mail Analytics/Johnson/Wouter/03. GeoData map - R/Sierra Leone adm2", "SLE_adm2", verbose = TRUE, stringsAsFactors = FALSE)
sl_adm2_months_DF <- fortify(sl_adm2_months, region = "NAME_2")
# Getting the correct District names
colnames(sl_adm2_months_DF)[7] <- "District"
sl_adm2_months_DF$District <- ifelse(sl_adm2_months_DF$District == "Western Rural", "Western Area Rural", as.character(sl_adm2_months_DF$District))
sl_adm2_months_DF$District <- ifelse(sl_adm2_months_DF$District == "Western Urban", "Western Area Urban", as.character(sl_adm2_months_DF$District))
sl_adm2_months_DF$District <- as.factor(sl_adm2_months_DF$District)
#Extracting district names for plotting
sl_adm2_months_names_DF <- data.frame(long = coordinates(sl_adm2_months[, 1]), lat = coordinates(sl_adm2_months[, 2]))
sl_adm2_months_names_DF[, "ID_2"] <- sl_adm2_months@data[, "ID_2"]
sl_adm2_months_names_DF[, "NAME_2"] <- sl_adm2_months@data[, "NAME_2"]
# Subset May data
sl_Month <- data[data$Country == "Sierra Leone" & data$Date <= as.Date(date), ]
sl_Month <- droplevels(sl_Month)
sl_Month[is.na(sl_Month)] <- 0
confirmed <- ddply(sl_Month, .(Localite), function(x){max(x$cmlConfirmed.cases, na.rm = T)})
cases <- ddply(sl_Month, .(Localite), function(x){max(x$cmlCases, na.rm = T)})
deaths <- ddply(sl_Month, .(Localite), function(x){max(x$cmlDeaths, na.rm = T)})
sl_Month <- merge(cases, deaths, by = "Localite")
sl_Month <- merge(sl_Month, confirmed, by = "Localite")
sl_Month <- droplevels(sl_Month)
sl_Month <- droplevels(sl_Month)
colnames(sl_Month)<- c("District", "totalCases", "totalDeaths", "totalConfirmed")
sl_Month <- sl_Month[-which(sl_Month$District == "National"),]
# Merging Month data with District polygons
sl_adm2_Month <- merge(sl_adm2_months_DF, sl_Month, by = "District", all.x = TRUE)
sl_adm2_Month$totalCases <- as.numeric(sl_adm2_Month$totalCases)
sl_adm2_Month$totalDeaths <- as.numeric(sl_adm2_Month$totalDeaths)
sl_adm2_Month$totalConfirmed <- as.numeric(sl_adm2_Month$totalConfirmed)
#NA to 0 for values missing for districts
sl_adm2_Month[is.na(sl_adm2_Month)] <- 0
#Sorting
sl_adm2_Month <- sl_adm2_Month[order(sl_adm2_Month$District, sl_adm2_Month$order), ]
# Prints & Views
print(head(sl_Month))
View(sl_Month)
View(sl_adm2_Month)
Sys.setlocale("LC_TIME", "English")
# Plotting Cases
return ({
ggplot() +
geom_polygon(data = sl_adm2_Month, aes(x = long, y = lat, group = group,
fill = variable), colour = "white") +
geom_text(data = sl_adm2_months_names_DF, aes(label = NAME_2, x = long.1, y = lat.2, group = NAME_2), size = 3) +
# labs(title = paste("Ebola", str_sub(as.character(variable), 6, -1), "cases by district in Sierra Leone - until", format(as.Date(date), "%B %Y"))) +
xlab("") +
ylab("") +
theme_gray() +
theme(legend.position = "bottom")
})
}
# Plotting the months - variable = second input and must be IN c(totalDeaths, totalCases, totalConfirmed)
plotMonths(final_dataset, "totalCases", "2014-05-31")
我在论坛上阅读了一些类似的问题,但无法解决我的问题。
非常欢迎任何有关如何解决此问题的帮助!
【问题讨论】:
-
variable似乎不是您的数据框中的一列。您应该以某种方式将variable添加到sl_adm2_Month,这应该可以解决您的错误。 -
哦,如果
variable是一个字符串,表示用于fill的列,那么您应该查看aes_string -
是的,你可能想要
aes_string(x = "long", y = "lat", group = "group", fill = variable)或类似的。 -
非常感谢大家,aes_string 似乎工作得很好!我过去一直在使用 aes 并且从来没有遇到过我必须使用 aes_string 的情况......只是查看了 aes 和 aes_string 之间的区别,现在我很清楚为什么我需要使用这个。 :)
-
感谢@Axeman 提供的信息,用正确的答案更新了这个主题。