SQL查询以打印名称和顺序打印职业

Question

查询 OCCUPATIONS 中所有名称的按字母顺序排列的列表，紧随其后的是每个职业的第一个字母作为括号（即：括在括号中）。

例如：

AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S)

查询OCCUPATIONS中每个职业出现的次数。将出现的次数按升序排序，并按以下格式输出：

SELECT name||'('||SUBSTR(occupation, 1, 1)||')'
FROM occupations
ORDER BY name

UNION

SELECT "There are a total of"|| count(*) from occupations group by occupation;

Answer 1

带代码的输入和输出示例：

create table ns_occupations(name varchar(20));

insert into NS_OCCUPATIONS values('AActorName');

insert into NS_OCCUPATIONS values('ADoctorName');

insert into NS_OCCUPATIONS values('AProfessorName');

insert into NS_OCCUPATIONS values('ASingerName');


insert into NS_OCCUPATIONS values('ASingerName');

select * from NS_OCCUPATIONS;

SELECT name||'('||SUBSTR(name, 2, 1)||')'  shortname,count(*)  no_of_occupations
FROM ns_occupations
group by name||'('||SUBSTR(name, 2, 1)||')';

output:
ADoctorName(D)  1
AActorName(A)   1
AProfessorName(P)   1
ASingerName(S)  2

Answer 2

当你使用UNION/UNION ALL时，ORDER BY必须是最后一个子句：

SELECT name||'('||SUBSTR(occupation, 1, 1)||')' AS col
FROM occupations
union
select 'There are a total of'|| count(*) 
from occupations 
group by occupation
ORDER BY CASE WHEN col LIKE 'There are a total%' THEN 1 ELSE 0 END, col;

Answer 3

从职业中选择名称+'('+left(occupation,1)+')' 按名称排序 联盟 select '总共有'+convert(nvarchar,count(occupation))+' '+occupation+'s.'从职业 按职业分组 按数量（职业）排序；

Answer 4

select concat(name, '(',left(occupation,1),')') 
from occupations 
order by name asc;

select 'There are a total of ' ,count(occupation) ,concat(lower(occupation), 's.') 
from occupations
group by occupation 
order by count(occupation) asc, occupation asc;

//status of Testcase passed