oracle不存在里面不存在

Question

当我运行这个查询时，伙计们：

SELECT * FROM big_table big
WHERE sum_number = 1
 AND NOT EXISTS ( SELECT 1
                  FROM smal_table smal
                  WHERE other_number = big.other_number
                )

我得到 4 个结果，但是当我运行这个时

SELECT * FROM big_table big
WHERE sum_number = 1
 AND NOT EXISTS ( SELECT 1
                  FROM smal_table smal
                  WHERE other_number = big.other_number
                  AND NOT EXISTS ( SELECT 1
                                    FROM and_another_table another
                                    WHERE and_another_number = big.and_another_number
                                 )
                )

我从 big_table 获取所有行。 有谁知道为什么会发生这种情况？ 我想做一个查询，显示 big_table 中不存在于 smal_table 中的所有行，但如果它存在于小表中，我只想要 and_another_table 中不存在的行 谁能帮帮我？

编辑：我想要 big_table 中不在 small_table 中的行加上 big_table 中在 small_table 但不在 and_another_table 中的行

Answer 1

我认为逻辑是您希望大表中的行不在小表或另一个表中。如果是这样，这应该做你想要的：

SELECT *
FROM big_table big
WHERE sum_number = 1 AND
      (NOT EXISTS (SELECT 1
                   FROM small_table smal
                   WHERE other_number = big.other_number
                  ) OR
       NOT EXISTS (SELECT 1
                   FROM and_another_table another
                   WHERE and_another_number = big.and_another_number
                  )
      );

编辑：

根据下面的评论，where 子句将是：

WHERE sum_number = 1 AND
      (NOT EXISTS (SELECT 1
                   FROM small_table smal
                   WHERE other_number = big.other_number
                  ) OR
       EXISTS (SELECT 1
               FROM and_another_table another
               WHERE and_another_number = big.and_another_number
              )
      );