Oracle SQL - 不存在 - 值列表中不存在字符串

Question

背景：对于一个 SPRIDEN_id，sprhold_hldd_code 可能有一个或多个值或 NO 值。

我需要选择 SP.SPRIDEN_ID、SP.SPRIDEN_LAST_NAME、SP.SPRIDEN_FIRST_NAME、SR.SHRDGMR_SEQ_NO、SR.SHRDGMR_PROGRAM

哪里 (sh.sprhold_hldd_code = 'RH') 不存在。

到目前为止，没有返回任何记录。

我发现如果我在 sh.sprhold_hldd_code = 'Z' 中放入一个不在可能值列表中的代码（例如 Z），那么它会返回结果。

DATA: (column names abbreviated)
SPRIDEN_ID   SPRIDEN_LAST   SPRIDEN_FIRST  SHRDGMR_SEQ_NO   SHRDGMR_PROGRAM sh.sprhold_hldd_code
100001       Smith          Sue            1                ALHE            RH
100001       Smith          Sue            1                ALHE            AA
100001       Smith          Sue            1                ALHE            BB
100005       Conners        Tim            1                BUSN            RH
100008       Occent         Mary           1                MATH            CC
100008       Occent         Mary           1                MATH            AA

Expected Results: Mary is the only record that does NOT have the RH code.

SPRIDEN_ID   SPRIDEN_LAST_NAME   SPRIDEN_FIRST_NAME  SHRDGMR_SEQ_NO  SHRDGMR_PROGRAM
100008       Occent              Mary                1                MATH              

但我没有收到任何结果。

CODE:
Select SP.SPRIDEN_ID, SP.SPRIDEN_LAST_NAME, SP.SPRIDEN_FIRST_NAME, SR.SHRDGMR_SEQ_NO,          SR.SHRDGMR_PROGRAM
from spriden SP
join SHRDGMR SR on SP.SPRIDEN_PIDM = SR.SHRDGMR_PIDM
join SPRHOLD SH on sp.spriden_pidm = sh.sprhold_pidm
where SR.SHRDGMR_DEGS_CODE = 'PN'
  and SR.SHRDGMR_TERM_CODE_GRAD >= '201489'
  and sp.spriden_change_ind is NULL
and not exists
(select sh.sprhold_pidm
from sprhold sh
where sh.sprhold_hldd_code = 'RH')

Answer 1

要获得您想要的数据，我建议使用带有having 子句的聚合：

Select SP.SPRIDEN_ID, SP.SPRIDEN_LAST_NAME, SP.SPRIDEN_FIRST_NAME, SR.SHRDGMR_SEQ_NO, 
       SR.SHRDGMR_PROGRAM
from spriden SP join
     SHRDGMR SR
     on SP.SPRIDEN_PIDM = SR.SHRDGMR_PIDM join
     SPRHOLD SH
     on sp.spriden_pidm = sh.sprhold_pidm
where SR.SHRDGMR_DEGS_CODE = 'PN' and
      SR.SHRDGMR_TERM_CODE_GRAD >= '201489' and
     sp.spriden_change_ind is NULL
group by SP.SPRIDEN_ID, SP.SPRIDEN_LAST_NAME, SP.SPRIDEN_FIRST_NAME, SR.SHRDGMR_SEQ_NO, 
         SR.SHRDGMR_PROGRAM
having sum(case when sh.sprhold_hldd_code = 'RH' then 1 else 0 end) = 0;

您的方法有两个问题。第一个是子查询返回 true 或 false 并影响原始查询中的所有行。你真的想要一个相关的子查询。但是，即使你做对了，你也会为 Mary 返回重复的行。这解决了这两个问题。

Answer 2

你可以做些小改变，然后试试

and sh.sprhold_pidm not in
(select sh.sprhold_pidm
from sprhold sh
where sh.sprhold_hldd_code = 'RH')