MySQL - 按 15 分钟间隔对时间范围进行分组

Question

所以，我有一个计时表，用于跟踪我的员工在登录不同状态时所花费的时间。看起来是这样的：

Employee_ID     Queue             StartTime            End Time
   121509      'Break'      2018-05-17 13:31:54  2018-05-17 13:47:02
   121509      'Working'    2018-05-17 13:47:04  2018-05-17 15:05:45
   121509      'Unavail.'   2018-05-17 15:05:46  2018-05-17 15:32:01

等等。我的目标是汇总所有员工在每个队列状态中花费的时间（通过从 EndTime 中减去 StartTime 得出），并将该汇总按 15 分钟间隔分组。我在做的是这样的：

concat(
    time_format(convert_tz(StartTime,'UTC','America/Denver'),'%H'),
    ':',
    case
        when minute(convert_tz(StartTime,'UTC','America/Denver')) < 15
            then '00'
        when minute(convert_tz(StartTime,'UTC','America/Denver')) < 30
            then '15'
        when minute(convert_tz(StartTime,'UTC','America/Denver')) < 45
            then '30'
        else '45'
    end,
    ':00'
) as 'Interval',

但是，通过这种方式进行分组，我意识到如果我以这种方式对事物进行分组，那么在队列中花费的任何时间都将仅计入员工登录的第一个时间间隔，而不是拆分StartTime 和 Endtime 之间的时间范围所包围的所有间隔中的时间。

所以，我的问题是：我如何对我的数据进行分组，以便如果给定的时间范围超过了它开始的 15 分钟间隔，那么它就会开始为 下一个 15 分钟的间隔计数？

示例输出：

Employee_ID   Interval      Queue    QueueTime
   121509        13:30      'Break'   00:14:54
   121509        13:45      'Break'   00:02:02
   121509        13:45     'Working'  00:13:58
   121509        14:00     'Working'  00:15:00
   121509        14:15     'Working'  00:15:00
   121509        14:30     'Working'  00:02:58
   121509        14:30     'Unavail.' 00:08:13
   121509        14:30     'Break'    00:03:28

Answer 1

我猜您会想要获取时间戳差异，然后按员工和队列类型分组。像这样的查询应该适合您：

SELECT 
    Employee_ID,
    Queue,
    SUM(TIMESTAMPDIFF(MINUTE,
        StartTime,
        EndTime)) AS Time
FROM
    EmployeeTable
GROUP BY Employee_ID , Queue;

Answer 2

好的。花了一些时间，但我在 RToyo 的帮助下弄明白了：

首先：创建一个包含 15 分钟间隔的列表：

        select 
        addtime(time('00:00:00'),sec_to_time(900 * (a.a + b.a * 10))) as 'IntervalStart',
        addtime(time('00:14:59'),sec_to_time(900 * (a.a + b.a * 10))) as 'IntervalEnd'
    from (
        select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
        cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
    where
        addtime(time('00:00:00'),sec_to_time(900 * (a.a + b.a * 10))) between '06:00:00' and '18:45:00'

下一步：通过测试 StartTime 和 Endtime 字段之间的重叠来加入计时表：

left join (     select 
        addtime(time('00:00:00'),sec_to_time(900 * (a.a + b.a * 10))) as 'Interval Start',
        addtime(time('00:14:59'),sec_to_time(900 * (a.a + b.a * 10))) as 'Interval End'
    from (
        select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
        cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
    where
        addtime(time('00:00:00'),sec_to_time(900 * (a.a + b.a * 10))) between '06:00:00' and '18:45:00') as Intervals
on timekeepingtable.StartTime <= Intervals.IntervalStart
and timekeepingtable.EndTime >= Intervals.IntervalEnd

然后只需将 StartTime 和 EndTime 字段修改为以间隔为界：

        if(time(pgrp.StartTime) < Intervals.IntervalStart,Intervals.IntervalStart,time(pgrp.StartTime)) as 'Start Time',
    if(time(pgrp.EndTime) > Intervals.IntervalEnd, Intervals.IntervalEnd,time(pgrp.EndTime)) as 'End Time',