【问题标题】:Add parameter on UITapGestureRecognizer在 UITapGestureRecognizer 上添加参数
【发布时间】:2016-05-12 04:03:04
【问题描述】:

我想问一下如何在我的 UILabel 上的 UITapGestureRecognizer 上添加参数。到目前为止,这是我得到的:

self.feedSource.text = source_link
                    self.feedSource.userInteractionEnabled = true
                    let feedSourceTapGesture = UITapGestureRecognizer(target: self, action: Selector("openLinkFromFeedSource"))
                    self.feedSource.addGestureRecognizer(feedSourceTapGesture)


func openLinkFromFeedSource() {
        print("tapped")
    }

我想要实现的是当我点击标签时,我可以从 openLinkFromFeedSource 获取 self.feedSource.text 的值

谢谢!

【问题讨论】:

    标签: ios swift uilabel uitapgesturerecognizer


    【解决方案1】:

    你应该从这样的点击手势动作中得到这个:

    func didTapOnView(tap: UITapGestureRecognizer) {
        let label = tap.view
        // do with that label
    }
    

    【讨论】:

    • 您应该提到action 参数需要更新以反映参数的添加。
    【解决方案2】:

    试试这个

    self.feedSource.userInteractionEnabled = true
    let feedSourceTapGesture = UITapGestureRecognizer(target: self, action: Selector("openLinkFromFeedSource:"))
    self.feedSource.addGestureRecognizer(feedSourceTapGesture)
    
    
    func openLinkFromFeedSource(sender: UITapGestureRecognizer) {
      let label = sender.view
    
        print("tapped")
    }
    

    【讨论】:

    • 为什么有人反对这个答案?这比其他答案要好得多。
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