【发布时间】:2023-07-10 19:44:01
【问题描述】:
我对 Swift 和 Alamofire 很陌生,我想要完成的是发送一个数据结构,如下所示:
{
"name" : "Test name",
"intention" : "Purpose of practice test",
"id_frequency" : "1",
"member": [
{
"id_member" : "1",
"email" : "member1@gmail.com",
"id_member_type" : 1
},
{
"id_member" : "4",
"email" : "member2@gmail.com",
"id_member_type" : 3
},
{
"id_member" : "7",
"email" : "member3@gmail.com",
"id_member_type" : 3
},
{
"id_member" : "5",
"email" : "member4@gmail.com",
"id_member_type" : 3
},
{
"id_member" : "6",
"email" : "member5@gmail.com",
"id_member_type" : 3
}
]
}
我着手构建所需 json 的方式如下:
var membersArray = [AnyObject]()
for i in 0..<members.count {
let json: [String: Any] = [
"id_member": members[i].idMember!,
"email": members[i].email!,
"id_member_type": "\(Int(members[i].idMemberType)!)",
]
membersArray.append(json as AnyObject)
}
let jsonMembers = JSON(membersArray)
let jsonObject: [String: Any] = [
"member" : jsonMembers,
"name": name!,
"intention": intention!,
"id_frequency": frequency!
]
let jsonUpdate = JSON(jsonObject)
有了这个结构化的 json,上面的行 (jsonUpdate)。我继续执行 webService。
WevServices.createRequest(requestInfo: jsonUpdate) { (result) in
print(result)
}
我的 webservice 方法,如下所示:
static func createRequest(requestInfo: JSON, completion: @escaping (_ result: String) -> Void){
let url = URL(string: "http://ws.someURL.com/CreateRequest")
let parameters: [String : Any] = ["name" : "\(requestInfo["name"])", "intention" : "\(requestInfo["intention"])", "id_frequency" : "\(requestInfo["id_frequency"])", "member": requestInfo["member"]]
Alamofire.request(url!, method: .post, parameters: parameters, encoding: URLEncoding.httpBody).responseString { response in
print(response)
}
}
我从服务器收到一个错误,表明发送数据不正确。
注意:我的应用程序使用 Lumen 作为后端。
【问题讨论】:
-
从 json 中你想获取什么 member 数据并作为参数发送?
标签: ios json swift alamofire lumen