XMPP房间邀请好友IOS答案

【问题标题】：XMPP Room Invite Friend IOSXMPP房间邀请好友IOS
【发布时间】：2013-11-22 06:34:50
【问题描述】：

我在 ios 中使用 XMPP 框架。如何邀请其他用户进行群聊？

 [xmppRoom1 inviteUser:[XMPPJID jidWithString:@"abc@domain.com"] withMessage:@"Come Join me"];

【问题讨论】：

标签： ios iphone objective-c ios6 xmpp

【解决方案1】：

MUC中可以一一邀请多个用户：

for (int contactIndex = 0; contactIndex <contactsToInviteArray.count; contactIndex++)
{
    NSString * inviteUserJID = [NSString stringWithFormat:@"%@@%@",[contactsToInviteArray enter code hereobjectAtIndex:contactIndex], SERVER_NAME];
    [xmppRoom1 inviteUser:[XMPPJID jidWithString:inviteUserJID] withMessage:@"Come Join me"];

}

【讨论】：

在调用邀请函数之前我们是否需要执行此代码。 _xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:xmppRoomCoreDataStorage jid:groupJabId dispatchQueue:dispatch_get_main_queue()]; [_xmppRoom 激活：[[CLXMPPDelegate sharedManager] xmppStream]]； [_xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()]; NSXMLElement *history = [NSXMLElement elementWithName:@"history"]; [history addAttributeWithName:@"maxstanzas" stringValue:@"0"]; [_xmppRoom joinRoomUsingNickname:userMO.closrr_id history:nil];

【解决方案2】：

此代码对我有用。

XMPPRoomMemoryStorage *roomMemoryStorage = [[XMPPRoomMemoryStorage alloc] init];
XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:roomMemoryStorage jid:[XMPPJID jidWithString:@"Groupname"] dispatchQueue:dispatch_get_main_queue()];
[xmppRoom activate:xmppStream];
[xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()];
[xmppRoom inviteUser:[XMPPJID jidWithString:@""] withMessage:[NSString stringWithFormat:@"Come Join me"] listusers:@" array with list of users JID "];

【讨论】：