返回该数字输入的 Python 不正确，但它是正确的答案

【问题标题】：Python returning that number input is incorrect, but it is correct返回该数字输入的 Python 不正确，但它是正确的
【发布时间】：2022-01-23 03:41:40
【问题描述】：

我制作了一个 python 程序，可以在随机数或字母之间进行选择，然后用户尝试猜测它，但是当程序选择一个数字并正确猜测到确切数字时，它会返回该数字用户输入不正确。

这是我的代码：

import math
import random
import string


count = 0
numberroll = random.randint(1,10)
stringroll = random.choice(string.ascii_letters)

chooseroll = random.choice([numberroll, stringroll.lower()])

# print(chooseroll)

count = 0
if chooseroll == numberroll:
    usernumberguess = input("Your guess: ")
    if usernumberguess.isdigit():
        print("It is a number!")
        count += 1
    else:
        print("That is not a number...")
    if usernumberguess.isdigit() == numberroll:
        print("Correct number!")
        count += 2
    else:
        print("Better luck next time!")

if chooseroll == stringroll.lower():
    userstringguess = input("Your guess: ")
    if userstringguess.isalpha():
        print("It is a letter!")
        count += 1
    else:
        print("That is not a letter...")
    if userstringguess.lower() == stringroll.lower():
        print("Correct letter!")
        count += 2
    else:
        print("Incorrect! Better luck next time!")

# print(count)

有没有办法解决这个问题？提前致谢！

【问题讨论】：

你能分享更多你的代码吗？不能运行就很难调试。

标签： python string random numbers choice

【解决方案1】：

这部分if usernumberguess.isdigit() == numberroll:可能有问题：isdigit()返回True或False，你检查是不是numberroll。您可以在猜测是数字的情况下检查猜测是否正确。您还需要将输入（字符串）转换为int。

if chooseroll == numberroll:
    usernumberguess = input("Your guess: ")
    if usernumberguess.isdigit():
        print("It is a number!")
        usernumberguess = int(usernumberguess)
        count += 1
        if usernumberguess == numberroll:
            print("Correct number!")
            count += 2
        else:
            print("Better luck next time!")
    else:
        print("That is not a number...")

我会添加更多代码用于调试目的，以便您查看问题所在：

import random
random.seed(0)
count = 0
numberroll = random.randint(0, 9)
print(f"the user has to guess: {numberroll}")

usernumberguess = input("your guess: ")
print(f"your guess is {usernumberguess}")

if usernumberguess.isdigit():
    print("your guess is a number")
    usernumberguess = int(usernumberguess)
    count += 1
    if usernumberguess == numberroll:
        print("your guess is correct")
        count += 2
    else:
        print("your guess is not correct")
else:
    print("your guess is not a number")

【讨论】：