【发布时间】：2013-05-29 16:19:16
【问题描述】：
我在一个文件夹中有一组文件，所有文件都以相似的名称开头，除了一个。这是一个例子：
Coordinate.txt
Spectrum_1.txt
Spectrum_2.txt
Spectrum_3.txt
.
.
.
Spectrum_11235
我可以列出指定文件夹中的所有文件，但列表不是按频谱编号升序排列的。示例：我在执行程序时得到如下结果：
Spectrum_999.txt
Spectrum_9990.txt
Spectrum_9991.txt
Spectrum_9992.txt
Spectrum_9993.txt
Spectrum_9994.txt
Spectrum_9995.txt
Spectrum_9996.txt
Spectrum_9997.txt
Spectrum_9998.txt
Spectrum_9999.txt
但是这个顺序是不正确的。 Spectrum_999.txt 后面应该有 Spectrum_1000.txt 文件。任何人都可以帮忙吗？代码如下：
import java.io.*;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;
public class FileInput {
public void userInput()
{
Scanner scanner = new Scanner( System.in );
System.out.println("Enter the file path: ");
String dirPath = scanner.nextLine(); // Takes the directory path as the user input
File folder = new File(dirPath);
if(folder.isDirectory())
{
File[] fileList = folder.listFiles();
Arrays.sort(fileList);
System.out.println("\nTotal number of items present in the directory: " + fileList.length );
// Lists only files since we have applied file filter
for(File file:fileList)
{
System.out.println(file.getName());
}
// Creating a filter to return only files.
FileFilter fileFilter = new FileFilter()
{
@Override
public boolean accept(File file) {
return !file.isDirectory();
}
};
fileList = folder.listFiles(fileFilter);
// Sort files by name
Arrays.sort(fileList, new Comparator()
{
@Override
public int compare(Object f1, Object f2) {
return ((File) f1).getName().compareTo(((File) f2).getName());
}
});
//Prints the files in file name ascending order
for(File file:fileList)
{
System.out.println(file.getName());
}
}
}
}
【问题讨论】：
标签： java file sorting arraylist