【问题标题】:Serialize instance of a class deriving from DynamicObject class序列化派生自 DynamicObject 类的类的实例
【发布时间】:2018-03-05 20:06:27
【问题描述】:

我有一个派生自 DynamicObject 类的类。在调用 JsonConvert.SertializeObject 时,没有任何动态属性被序列化。

类定义为,

        public class Component : DynamicObject
        {
        // The inner dictionary.
        public Dictionary<string, object> dictionary
            = new Dictionary<string, object>();

        [JsonProperty(PropertyName = "id")]
        public string Id { get; set; }

        // If you try to get a value of a property 
        // not defined in the class, this method is called.
        public override bool TryGetMember (
            GetMemberBinder binder, out object result)
            {
            // Converting the property name to lowercase
            // so that property names become case-insensitive.
            string name = binder.Name.ToLower();

            // If the property name is found in a dictionary,
            // set the result parameter to the property value and return true.
            // Otherwise, return false.
            return dictionary.TryGetValue(name, out result);
            }

        // If you try to set a value of a property that is
        // not defined in the class, this method is called.
        public override bool TrySetMember (
            SetMemberBinder binder, object value)
            {
            // Converting the property name to lowercase
            // so that property names become case-insensitive.
            dictionary[binder.Name.ToLower()] = value;

            // You can always add a value to a dictionary,
            // so this method always returns true.
            return true;
            }
        }

然后我这样做,

dynamic component = new Component();
component.test = "123";

JsonConvert.SerializeObject(component);

【问题讨论】:

    标签: c# serialization json.net expandoobject dynamicobject


    【解决方案1】:

    你需要覆盖DynamicObject.GetDynamicMemberNames:

    public override IEnumerable<string> GetDynamicMemberNames()
    {
        return dictionary.Keys;
    }
    

    【讨论】:

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