字符串管理数组

Question

我有一个字符串数组，我想把这个数组的一个区间内的所有字符串都取出来，直到字符串不包含任何东西。

类似：

string [] arrayReading = {
  "e","x","a","takefromhere",
  "keeptaking","keeptaking","dont'ttakefromhere","m","p","l","e"
};

我试过了：

        List<string> result = null;

        for (int i = 0; i < arrayReading.Length; i++)
        {
            if (arrayReading[i].Contains("takefromhere"))
            {
                result.Add(arrayReading[i]);

                if (!arrayReading[i + 1].Contains("dont'ttakefromhere"))
                {
                    result.Add(arrayReading[i + 1]);

                    if (!arrayReading[i + 2].Contains("dont'ttakefromhere"))
                    {
                        rescription.Add(arrayReading[i + 1]);
                    }
                }
            }
        }

似乎有效，但它并不是我想要的那样动态，因为也许我需要在“takefromhere”和“don'ttakefromhere”之间取 20 个值。

Answer 1

查询时你可以试试Linq：

 using System.Linq;

 ...

 List<string> result = arrayReading
   .SkipWhile(item => item != "takefromhere") 
   .TakeWhile(item => item != "dont'ttakefromhere")
   .ToList();

或者如果你想要旧的循环解决方案：

 List<string> result = new List<string>(); 

 bool taking = false;

 foreach (string item in arrayReading) {
   if (!taking) 
     taking = item == "takefromhere";

   if (taking) {
     if (item == "dont'ttakefromhere")
       break;

     result.Add(item);
   } 
}

让我们看看：

Console.Write(string.Join("; ", result));

结果：

takefromhere; keeptaking; keeptaking