【发布时间】:2016-11-15 17:48:44
【问题描述】:
我在数据库中有两个表(table_1 和 table_2),每个表都有一个名为 Name 的相互列。
我目前正在使用以下代码仅从table_1 导入一些数据(Name,status):
/* database section start */
$mysqli = new mysqli("z","z","z","z");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
/* database section end */
// Choose Relevant items, and turn them into an array
$item_array = array(
'item1',
'item2',
'item3'
);
//implode items, turn into string
$item_implode = join("','", $item_array);
//declare an overall array for result
$product = array();
$result = $mysqli->query("SELECT Name, Status as status from table_1 where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode');");
while($row = $result->fetch_assoc()) {
$product_name = $row['Name'];
// find all keys in $item_array which value is the products
$keys = array_keys($item_array, $product_name);
foreach ($keys as $key) {
// add values for these keys
$product[$key + 1]["Name"] = $row['Name'];
$product[$key + 1]["status"] = $row['status'];//
}
}
如果我还想从table_2 导入数据(例如,名为color、date_added 的列),我应该在此代码中添加什么?
我的目标是拥有这些钥匙:
$product[$x]["Name"]
$product[$x]["status"]
$product[$x]["color"]
$product[$x]["date_added"]
编辑:
那个长线程没有回答我的问题。该代码与我正在使用的代码不相似,我想知道如何在这个具体案例中准确地应用 UNION。
我尝试过使用:
$result = $mysqli->query
("(SELECT Name, status as status from table_1 )
UNION
(SELECT Name, color as color from table_2 )
where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode');");
while($row = $result->fetch_assoc()) {
但我在最后一行遇到致命错误。
EDIT2:
还是报错:
$result = $mysqli->query
("(SELECT Name, status as statu table_1 where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode') )
UNION (SELECT color from table_2 where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode') );");
while($row = $result->fetch_assoc()) {
【问题讨论】: