使用 REGEX 从 URL 变体中删除不需要的参数 [关闭]答案

【问题标题】：Removing unwanted param from URL variations with REGEX [closed]使用 REGEX 从 URL 变体中删除不需要的参数 [关闭]
【发布时间】：2021-09-28 21:43:42
【问题描述】：

是否有可能从 URI 中删除一些不需要的参数 unwanted，以使最终结果提供正确的 uri？

问题是我想要删除的 url 中有不需要的参数。我试过了，但是 & 和 ?应该保留在适当的位置以不破坏网址

(unwanted=.*?)\\

https://regex101.com/r/CXEuqH/1

this is clean uri with no params - should remain unchanged 
(should be replaced to: /some-clean-part-of-url-012567):
22 sdff=\"a sdsdsd \" sfs f =\"/some-clean-part-of-url-012567\" saafa 42wsdf=\"sf  sdf sd 432\" asd


url with unwanted only and nothing else:
(should be replaced to: /url-with-unwanted-only):
asda ds3=\"afdaa \" asd ad a =\"/url-with-unwanted-only?unwanted=base-unwanted-value-0605\" aas asd =\"sddghf \"asdasd wsdf=\"sf  sdf sd 432\" a das 


uri with unwanted at the beginning and other one or more wanted params after it
(should be replaced to: /unwanted-at-the-beginning-plus-other-params-4560?wanted_params=wanted_values):
as da=\"hkgd\" a =\"/unwanted-at-the-beginning-plus-other-params-4560?unwanted=not-need-value-23333&wanted_param=wanted_value\" asd =\"sddd8963ghf \" asdasdasd 


uri with unwanted at the end
(should be: unwanted-at-the-end-789870?wanted_param=wanted_value):
asda asd =\"sddwsd333ghf \"asdasdsd as as =\"/unwanted-at-the-end-789870?wanted_param=wanted_value&unwanted=unwanted-value-1-1s\" ad fd df sasd =\"sfe352ddghf \" asdasddf 


uri with unwanted in the middle
(should be: /unwanted-in-the-middle-38642?wanted_param=wanted_value&param_wanted=111):
as asd =\"sfe352ddghf \" as asd asd a =\"/unwanted-in-the-middle-38642?wanted_param=wanted_value&unwanted=some-unwanted-value0313&param_wanted=111\" ad sad asd a asd =\"sfe352ddghf \" as

我试过了，但是 & 和 ?应该保留在适当的位置以不破坏网址

最终结果应该是一个正确的 uri，没有不必要的“&”和“？”最后

【问题讨论】：

这些示例的期望输出是什么？如果你删除“？”从替代比“？”和“&”保持原位。
regex101.com/r/1F8hbh/1
问题中的每个示例都给出了所需的匹配项。投票重新开放。

标签： regex regexp-replace

【解决方案1】：

你可以使用

(?<=[?&])unwanted=[^&?=\s\\"]*&?

模式匹配：

(?<=[?&]) 正向向后看，断言左边是? 或&
unwanted= 字面匹配
[^&?=\s\\"]* 重复 0+ 次匹配除了negated character class 中列出的任何字符
&? 匹配可选的 & 符号

Regex demo

【讨论】：