如何解决json字典？

Question

如何解决这个我尝试了很多次但无法获取“business_details”数组的 JSON 数组。我只获取第一个“business_category_name” 然后“business_details”数组不获取。 我认为无法正确解释，请尝试理解并帮助我。 我很累

Json

 "status": [
{
  "business_category_name": "Banks\/Credit Unions\/Landers",
  "business_details": [
    {
      "img_url": "http:\/\/edutimeapp.com\/toshow\/chamber-of-commerc\/member-logo\/1464667619-pnc.jpg",
      "name": "PNC Bank",
      "des": "PNC offers a wide range of services for all our customers, from individuals and small businesses, to corporations and government entities",
      "address": "",
      "email": "andrea.kendall@pnc.com",
      "phone": "260-422-5922",
      "member_since": "2016-05-31",
      "img_company": "http:\/\/edutimeapp.com\/toshow\/chamber-of-commerc\/member-logo\/1464667619-pnc.jpg",
      "website": "",
      "city": "Fort Wayne",
      "state": "IN",
      "zip": "46808"
    }
  ]
},
{
  "business_category_name": "Cleaning Services",
  "business_details": [
    {
      "img_url": "http:\/\/edutimeapp.com\/toshow\/chamber-of-commerc\/uploads\/logo250.png",
      "name": "tsst company",
      "des": "rudurgg ",
      "address": "2005 s calhoun ",
      "email": "",
      "phone": "2602496687",
      "member_since": "2016-05-31",
      "img_company": "http:\/\/edutimeapp.com\/toshow\/chamber-of-commerc\/uploads\/logo250.png",
      "website": "",
      "city": "fort wayne",
      "state": "in",
      "zip": "46825"
    }
  ]
},

使用 Json 数据

 -(void)connectionDidFinishLoading:(NSURLConnection *)connection

{

 NSError *error;


NSLog(@"Error in receiving data %@",error);

NSMutableDictionary *json = [NSJSONSerialization JSONObjectWithData:response options:NSJSONReadingMutableLeaves  error:&error];

 NSLog(@"response data %@",json);


NSArray *results = [json objectForKey:@"status"];

 namearray= [results valueForKey:@"business_category_name"];

 emailarray = [results valueForKey:@"email"];

 [self.tableview reloadData];

 }

Answer 1

ViewController.m

@interface ViewController ()
{
     NSArray * yourArray;
}


NSLog(@"response data %@",json);
NSArray *results = [json objectForKey:@"status"];    
yourArray = [[[results objectAtIndex:0] valueForKey:@"business_details"] objectAtIndex:0];

这将为您提供 0 索引（第一个对象）的“business_details”输出

输出：

[
    {
      "img_url": "http:\/\/edutimeapp.com\/toshow\/chamber-of-commerc\/member-logo\/1464667619-pnc.jpg",
      "name": "PNC Bank",
      "des": "PNC offers a wide range of services for all our customers, from individuals and small businesses, to corporations and government entities",
      "address": "",
      "email": "andrea.kendall@pnc.com",
      "phone": "260-422-5922",
      "member_since": "2016-05-31",
      "img_company": "http:\/\/edutimeapp.com\/toshow\/chamber-of-commerc\/member-logo\/1464667619-pnc.jpg",
      "website": "",
      "city": "Fort Wayne",
      "state": "IN",
      "zip": "46808"
    }
]

如果你想在你的tableview 中使用它，那么你需要写indexPath.row 来代替索引，如下所示。

yourArray = [[[results objectAtIndex:indexPath.row] valueForKey:@"business_details"] objectAtIndex:0];

Answer 2

如果完整的输出是json 引用的字典，您可以这样做：

NSMutableDictionary *json = [NSJSONSerialization JSONObjectWithData:response 
                                                            options:NSJSONReadingMutableLeaves
                                                              error:&error];
NSArray *status = json[@"status"];
NSDictionary *firstStatus = status[0];
NSArray *businessDatails = firstStatus[@"business_details"]
// Likely you want to continue
NSDictionary *firstBusinessDetail = businessDetails[0];
NSMutableString *name = firstBusinessDetail[@"name"]M

或者把它们放在一起：

NSMutableArray *businessDatails = json[@"status"][0][@"business_details"];