【发布时间】:2017-02-04 10:09:17
【问题描述】:
我正在开发一个 API 端点,它将接受上传,然后立即转发到另一个 API。我不想将文件写入任何地方的磁盘,但我不确定以我的方式将文件临时存储在内存中是否正确。我能找到的所有示例都涉及将文件保存到磁盘。我已经在下面发布了我正在做的事情。我从第二个 API 得到的响应是我未能发布文件,但我可以看到它正在接收“userID”字段。有人可以指出我做错了什么,并可能建议这是否是解决此问题的最佳方法吗?
路由处理程序
func (r *Routes) forwardFile(w http.ResponseWriter, req *http.Request){
parameters := mux.Vars(req)
userID := parameters["userID"]
const maxFileSize = 1 * 1024 * 1024 // 1MB
// pull in the uploaded file into memory
req.ParseMultipartForm(maxFileSize)
file, fileHeader, err := req.FormFile("fileUpload")
if err != nil {
encodeResponse(w, req, response{obj: nil, err: err})
return
}
defer file.Close()
success, err := service.DoForwardFile(userID, file, fileHeader)
encodeResponse(w, req, response{obj: success, err: err})
}
服务处理程序
func (b *base) DoForwardFile(userID int, file multipart.File, fileHeader *multipart.FileHeader) (FileForwardedResponse, error) {
// start building our request to forward the file
var resp *http.Response
defer func() {
if resp != nil {
resp.Body.Close()
}
reportStat.Complete(0)
}()
// build a form body
body := &bytes.Buffer{}
bodyWriter := multipart.NewWriter(body)
// add form fields
bodyWriter.WriteField("userID", userID)
// add a form file to the body
fileWriter, err := bodyWriter.CreateFormFile("fileUpload", fileHeader.Filename)
if err != nil {
return FileForwardedResponse{}, err
}
// copy the file into the fileWriter
_, err = io.Copy(fileWriter, file)
if err != nil {
return FileForwardedResponse{}, err
}
// Close the body writer
bodyWriter.Close()
// build request url
apiURL := fmt.Sprintf("%s/v2/users/%d/files", config.APIURL, userID)
// send request
client := &http.Client{Timeout: time.Second * 10}
req, err := http.NewRequest("POST", apiURL, body)
resp, err = client.Do(req)
...
}
【问题讨论】:
标签: http file-upload go multipartform-data