如何迭代列表的笛卡尔积

Question

我想在 for 循环中使用 3 个（或任意数量的）列表和任意数量的元素进行迭代，例如：

from itertools import izip
for x in izip(["AAA", "BBB", "CCC"], ["M", "Q", "S", "K", "B"], ["00:00", "01:00", "02:00", "03:00"]):
    print x

但它给了我：

('AAA', 'M', '00:00')
('BBB', 'Q', '01:00')
('CCC', 'S', '02:00')

我想要：

('AAA', 'M', '00:00')
('AAA', 'M', '01:00')
('AAA', 'M', '02:00')
.
.

('CCC', 'B', '03:00')

其实我想要这个：

for word, letter, hours in [cartesian product of 3 lists above]
    if myfunction(word,letter,hours):
       var_word_letter_hours += 1

Answer 1

您想使用列表中的product：

from itertools import product

for word, letter, hours in product(["AAA", "BBB", "CCC"], ["M", "Q", "S", "K", "B"], ["00:00", "01:00", "02:00", "03:00"]):

演示：

>>> from itertools import product
>>> for word, letter, hours in product(["AAA", "BBB", "CCC"], ["M", "Q", "S", "K", "B"], ["00:00", "01:00", "02:00", "03:00"]):
...     print word, letter, hours
... 
AAA M 00:00
AAA M 01:00
AAA M 02:00
AAA M 03:00
...
CCC B 00:00
CCC B 01:00
CCC B 02:00
CCC B 03:00

Answer 2

使用itertools.product:

import itertools

for x in itertools.product(["AAA", "BBB", "CCC"],
                           ["M", "Q", "S", "K", "B"],
                           ["00:00", "01:00", "02:00", "03:00"]):
    print x

输出：

('AAA', 'M', '00:00')
('AAA', 'M', '01:00')
...
('CCC', 'B', '02:00')
('CCC', 'B', '03:00')

Answer 3

仅作记录，另一种解决方案只是嵌套for循环：

for a in ["AAA", "BBB", "CCC"]:
    for b in ["M", "Q", "S", "K", "B"]:
       for c in ["00:00", "01:00", "02:00", "03:00"]:
           x = (a, b, c)
           # Use x ...

在我看来，这比必须找出/记住itertools.product 函数的作用要清楚得多。使用它的唯一充分理由是，如果您处于更抽象的情况；例如您需要将迭代器传递给函数，而不是立即对其进行迭代，或者如果您有任意列表想要获取笛卡尔积（在这种情况下，您可以使用 product(*lists)）。