生成没有参数的主要参数

Question

在C编程语言中，是否可以不使用参数访问int argc或char **argv？我知道你们中的一些人可能会问为什么需要这样做，只是为了研究目的。

是否可以在不使用主参数变量的情况下生成 cmd 行参数？例如，为了说明一些我想到的伪代码，

LPTSTR cmd  = GetCommandLine();
splitted = cmd.split(" ") //split from spaces
char **someArgv.pushForEach Splitted, length++

你会有一个带有参数的someArgv 和length 作为argc，这真的有助于了解是否可以说明。

Answer 1

如果 OP already has 命令是一个字符串，那么：

• 形成字符串的副本

• 解析参数计数

• 分配给argv[]

• 为每个 argv[] 解析和标记副本

• 致电main()

---

#include <string.h>
#include <stdlib.h>
#include <stdio.h>

// Not standard, but commonly available
char *strdup(const char *s);

// Return length of token and adjust offset to the next one
// Adjust as needed
// Presently only ' ' are used to separate
// More advanced would have escape characters, other white-space, etc.
size_t tokenize(const char *s, size_t *offset) {
  // find following space
  size_t len = strcspn(s + *offset, " ");
  *offset += len;
  // find first non-space
  *offset += strspn(s + *offset, " ");
  return len;
}

int call_main(const char *cmd) {
  char *cmd2 = strdup(cmd);
  cmd2 += strspn(cmd2, " "); // skip leading spaces

  size_t offset = 0;
  int argc = 0;
  while (tokenize(cmd2, &offset) > 0) {
    argc++;
  }

  char **argv = malloc(sizeof *argv * ((unsigned)argc + 1u));
  offset = 0;
  for (int a = 0; a < argc; a++) {
    argv[a] = &cmd2[offset];
    size_t len = tokenize(cmd2, &offset);
    argv[a][len] = '\0';
  }
  argv[argc] = NULL;

  int retval = 0;
#if 0
  retval = main(argc, argv);
#else
  printf("argc:%d argv:", argc);
  for (int a = 0; a < argc; a++) {
    printf("%p \"%s\", ", argv[a], argv[a]);
  }
  printf("%p\n", argv[argc]);
#endif

  free(cmd2);
  free(argv);
  return retval;
}

样本

int main() {
  call_main("  name 123  abc  456 ");
}

argc:4 argv:0x800062322 "name", 0x800062327 "123", 0x80006232c "abc", 0x800062331 "456", 0x0

---

Pedantic：提供给main() 的字符串应该是可修改的。避免像

这样的代码

argv[1] = "Hello";
....
main(argc, argv);

Answer 2

#include <stdio.h>

int main(int argc, char *argv[]);

int callMain(void)
{
    char *argv[4];

    argv[0] = "binary";
    argv[1] = "param1";
    argv[2] = "param2";
    argv[3] = NULL;

    return main(3, argv);
}

int main(int argc, char *argv[])
{
    if (argc <= 1)
    {
        return callMain();
    }

    printf("ARGC: %u\n", argc);

    int i;
    for (i = 0; i < argc; i++)
        printf("ARG: %u - %s\n", i, argv[i]);

    return 0;
}