如何将其编写为模块？

Question

我想问一下，如何在Python中将以下内容编写为模块。

    if message.content.startswith('!guess'):
        # Game Status updating
        now_playing = discord.Game(name='Guessing Game')
        await self.change_status(game=now_playing, idle=False)

        await self.send_message(message.channel, 'Guess a number between 1 to 10')

        def guess_check(m1):
            return m1.content.isdigit()

        guess = await self.wait_for_message(timeout=5.0, author=message.author, check=guess_check)
        answer = random.randint(1, 10)
        if guess is None:
            fmt = 'Sorry, you took too long. It was {}.'
            await self.send_message(message.channel, fmt.format(answer))
            return
        if int(guess.content) == answer:
            await self.send_message(message.channel, 'You are right!')
        else:
            await self.send_message(message.channel, 'Sorry. It is actually {}.'.format(answer))

        # Game Status updating
        now_playing = discord.Game(name='')
        await self.change_status(game=now_playing, idle=False)

这样我就可以使用guessgame.guess() 来调用它

Answer 1

创建一个名为 guessgame.py 的 Python 模块文件，然后在其中定义：

"""
This is the module guessgame, it lives in the file guessgame.py
Put some documentation about your module here
"""
def guess(message):
   # Put your code here

然后从另一个模块，例如sample.py（或 Python/IPython shell 会话）你可以这样做：

import guessgame
guessgame.guess(message='something')       # What you wanted

RuntimeWarning: coroutine 'guess' 从未等待guessgame.guess()

# 'await' can only be used inside a coroutine
# if you want guess to be a coroutine, define it like below
async def guess(message):
   # Put your code that uses await
   # Now you can use await expressions

注意：

• 您使用的是await，这需要格外小心，请在此处阅读更多信息：https://www.python.org/dev/peps/pep-0492/#examples-of-await-expressions
• 不要在guessname.guess() 代码中重新定义guess 名称，因为您的函数已经被称为guess，如果您重新定义guess = ...，您将影响它
• 确保您的guessgame.guess() 传递了所有必需的参数，只是为了便于说明，我只包含了一个参数message
• 我看到您在该代码中使用了self，这表明这应该是一个类的方法，而不是一个独立的函数？只是需要牢记！