【发布时间】:2023-03-17 22:03:01
【问题描述】:
我想使用多张图像创建全景图。所以基本上,相机会在一个平面上线性平移,连续拍摄大约 20-30 张图像。我必须创建这些图像的全景图。我尝试过使用缝合功能以及查找特征并匹配它们然后变形的传统方法。但我不确定我是否做得正确。我该如何进行?
import imutils
import cv2
import glob
input_path = "/Users/akshayacharya/Desktop/Panorama/Raw
Data/riverside/*.jpg"
# input and sort the images
list_images = glob.glob(input_path)
list_sorted = sorted(list_images)
print(list_sorted)
# output path definition
output_path = "/Users/akshayacharya/Desktop/Panorama/Final
Panorama/finalpanoex1.jpg"
# initialize empty list and fill all images
images = []
for image in list_sorted:
image1 = cv2.imread(image)
image1 = cv2.resize(image1, (720, 480))
images.append(image1)
print("Read the images")
# this is the final list to stitch
final = [images[0]]
flag = True
print(len(images))
temp = [images[0]]
print(type(temp))
stitcher = cv2.createStitcher() if imutils.is_cv3() else
cv2.Stitcher_create()
i = 0
while(i < len(images)-1):
(status, stitched) = stitcher.stitch([temp[0], images[i+1]])
if status == 0:
final.append(images[i+1])
print(f"Succesfully stitch {i} to {i+1}")
i = i+1
temp[0] = stitched
continue
if status != 0:
print(f"Succesfully could not stitch {i} to {i + 1}")
for j in range(i+2, len(images)):
print(f"now trying {i} to {j}")
(status, stitchedd) = stitcher.stitch([temp[0], images[j]])
if status == 0:
print(f"Succesfully managed to stitch {i} to {j}")
final.append(images[j])
i=j
temp[0] = stitchedd
break
if status != 0:
print(f"Oops could not stitch {i} to {j}")
print(f"Will now see compatibility between {i} and {j+1}")
continue
i += 1
continue
cv2.imwrite(output_path, temp[0])
【问题讨论】:
-
'但我不确定我是否做得正确'。我们也不是。你的代码是什么,你的结果是什么,它们有什么问题?
-
@couka 我附上了代码和输出。请通过它
标签: python opencv sift panoramas