【发布时间】:2015-08-10 03:07:56
【问题描述】:
我想估计最大化函数 'func' 的参数 'k,ru,sigma' ('ru' 表示 r 上巴)
'func'公式是复杂的,所以我想上传图片来展示这个公式,但我没有足够的声誉。
import numpy as np
sigma,k,ru=0.01,0.001,5
p0=np.array([[0.01,0.01,6]])
p=np.array([[sigma,k,ru]])
def func(p,r):
T=91/365
y=1/(np.sqrt(2*(np.pi)*p[0]**2/(2*p[1])*(1-np.exp(-(2*p[1]*T)))))*np.exp((r-p[2]-np.exp(-(p[1]*T))*(r-p[2]))**2/(p[0]**2/((-4)*p[1])*(1-np.exp(-(2*p[1]*T)))))
return -y
from scipy.optimize import minimize
r=np.array([[1.45,2.5,2.6,1.67,1.2]])
# r has 1350 datas like this
res=minimize(func,p0,args=(r))
Traceback (most recent call last):
File "<ipython-input-9-b94a05d2ede8>", line 1, in <module>
res=minimize(func,p0,args=(r))
File "C:\Users\hyun su\Anaconda3\lib\site-packages\scipy\optimize\_minimize.py", line 419, in minimize
return _minimize_bfgs(fun, x0, args, jac, callback, **options)
File "C:\Users\hyun su\Anaconda3\lib\site-packages\scipy\optimize\optimize.py", line 837, in _minimize_bfgs
gfk = myfprime(x0)
File "C:\Users\hyun su\Anaconda3\lib\site-packages\scipy\optimize\optimize.py", line 282, in function_wrapper
return function(*(wrapper_args + args))
File "C:\Users\hyun su\Anaconda3\lib\site-packages\scipy\optimize\optimize.py", line 616, in approx_fprime
return _approx_fprime_helper(xk, f, epsilon, args=args)
File "C:\Users\hyun su\Anaconda3\lib\site-packages\scipy\optimize\optimize.py", line 556, in _approx_fprime_helper
grad[k] = (f(*((xk + d,) + args)) - f0) / d[k]
ValueError: setting an array element with a sequence.
我该如何解决这个问题?
【问题讨论】:
-
为什么
p和p0是二维的?您是否习惯了一种不支持任意维数组的语言? -
p 和 p0 应该是一维数组?那么 p =np.array([sigma,k,rup]) 是对的吗?