如果 powershell 中带有 -lt 日期值的语句多年来不能正确计算？

Question

我已经使用这个脚本大约一年了，似乎任何 22 年的值都没有被视为大于当前的 21 年...我的格式不正确吗？ csv 文件只是一个用户名，MM/DD/YY 格式。由于日期是明年而不工作的脚本的特定部分是：if($today -lt $EndDate)... 相对而言似乎可以工作几个月和几天，但不能工作几年？

在我的测试文件中，我有一个用户的日期为 22 年 1 月 3 日，脚本说日期已经结束（这意味着 $today 不小于 $enddate 值，实际上是明年）

任何指针？

$Import_csv = Import-Csv -Path "C:\temp\namesanddates.csv"

# Get today's date
$today = Get-Date -format MM/dd/yy

# Begin import csv process

$Import_csv | ForEach-Object {

    # Retrieve DN of User
    $UserDN = (Get-ADUser -Identity $_.Name).distinguishedName
    
    # Error check missing date - set to tomorrow
    $EndDate = (Get-Date).AddDays(1).ToString("MM/dd/yy")
    # Try to use date entered from file
    $EndDate   = (Get-Date $_.date).toString("MM/dd/yy")

    Write-Host "Current User:" $UserDN
    Write-Host "End Date in file:" $EndDate

if($today -lt $EndDate){
    Write-Host "User affected:" $UserDN
    Write-Host "Moving Accounts....." $UserDN

}else{
    Write-Output "User account date ended for:" $UserDN
    }
} 
Write-Host "Script Complete"

更新：感谢大家的反馈 - 通过取出 .toString 转换并排除任何格式 - Powershell 似乎在没有干预的情况下正确导入日期，然后比较有效。但是 - 如果我在代码中保留“-format MM/dd/yy”，小于比较仍然失败。两个变量都显示为日期时间和 | % gettype - 但它仍然说 01/03/22 小于今天的日期。

我将我的代码更改为以下内容，它现在似乎可以正常工作 - 似乎“格式”选项是 -lt 比较的原因。

$Import_csv = Import-Csv -Path "C:\temp\namesanddates.csv"

# Get today's date
$today = Get-Date 

# Begin import csv process

$Import_csv | ForEach-Object {

    # Retrieve DN of User
    $UserDN = (Get-ADUser -Identity $_.Name).distinguishedName
    
    # Error check missing date - set to today
    $EndDate = $today
    # Try to use date entered from file
    $EndDate = Get-Date $_.date

    Write-Host "Current User:" $UserDN
    Write-Host "End Date in file:" $EndDate

if($today -lt $EndDate){
    Write-Host "User affected:" $UserDN
    Write-Host "Moving Accounts....." $UserDN

}else{
    Write-Output "User account date ended for:" $UserDN
    }
} 
Write-Host "Script Complete"

Answer 1

正如其他人提到的，这里的问题是您将日期对象 ($today) 与字符串 ($EndDate) 进行比较

你需要修改如下

Import_csv = Import-Csv -Path "C:\temp\namesanddates.csv"

# Get today's date
$today = Get-Date -format MM/dd/yy

# Begin import csv process
$Import_csv | ForEach-Object {

# Retrieve DN of User
$UserDN = (Get-ADUser -Identity $_.Name).distinguishedName

# use date entered from file
EndDate   = Get-Date $_.date

Write-Host "Current User:" $UserDN
Write-Host "End Date in file: $($EndDate.toString("MM/dd/yy"))"

if($today -lt $EndDate){
    Write-Host "User affected:" $UserDN
    Write-Host "Moving Accounts....." $UserDN
}
else{
    Write-Output "User account date ended for:" $UserDN
    }
} 
Write-Host "Script Complete"

Answer 2

作为字符串，是有道理的。要做的一件事是在比较中让左侧为日期时间类型，右侧将自动转换。

$today = Get-Date  # 12/24/21
$today | % gettype

IsPublic IsSerial Name                                     BaseType
-------- -------- ----                                     --------
True     True     DateTime                                 System.ValueType


$today -lt '01/03/22'

True

通常人们使用这样的日期字符串，可以排序：

Get-Date -format yyyy/MM/dd

2021/12/24