传递给 Illuminate\Database\Eloquent\Builder::create() 的参数 1 必须是数组类型

Question

我有一个模型，我打算将输入保存到两个不同的表中，但出现错误

Symfony\Component\Debug\Exception\FatalThrowableError 参数 1 传递给 Illuminate\Database\Eloquent\Builder::create() 必须是 类型数组，给定对象，调用 C:\xampp\htdocs\blog\vendor\laravel\framework\src\Illuminate\Support\Traits\ForwardsCalls.php 第 23 行

第一个表是Transaction_in，第二个表是Transaction_in_detail。我计划使用idTransaction_in 作为两个表之间的连接器，并且该列不是主键（这是一个好习惯）？我可以将输入保存到Transcation_in 表，但仍然无法将输入保存到第二个表，而且我不知道如何将idTransaction_in 列作为连接器。

public function store(Request $request)
{
    $request->validate([
        'supplier_name' => 'required',
        'transaction_in_date' => 'required|before_or_equal:today',
        'device_type_name' => 'required',
        'device_brand_name' => 'required',
        'device_spec' => 'required|max:255',
        'price' => 'required',
        'amount' => 'required',
        'total_price' => 'required',
        'keterangan' => 'Nullable',

        ]);


    $transaction_in = new Transaction_in();
    $transaction_in->idTransaction_in = "0";
    $transaction_in->Supplier_id = $request->input('supplier_name');
    $transaction_in->tanggal_transaksi = $request->input('transaction_in_date');
    $transaction_in->save();
    $transaction_in->update(['idTransaction_in' => sprintf('TIN-%04d', $transaction_in->id)]);

    $lastid=Transaction_in::create($transaction_in)->idTransaction_in;
    if(count($request->device_type_name)>0){
        foreach ($request->device_type_name as $item => $v) {
            $data2=array(
                'Transaction_in_id' => $lastid,
                'DeviceType_id' => $request->device_type_name[$item],
                'DeviceBrand_id' => $request->device_brand_name[$item],
                'spek_device' => $request->device_spec[$item],
                'harga_device' => $request->price[$item],
                'jumlah_device' => $request->amount[$item],
                'total_harga_device' => $request->total_price[$item]
            );
            Transaction_in_detail::insert($data2);
        }
    }

    return redirect('/transactionsin')->with('success', 'Transaction success');
}

DeviceType_id 和 Devicebrand_id 是外键。

Answer 1

我看到你在这行有问题

$lastid=Transaction_in::create($transaction_in)->idTransaction_in;

$transaction_in 是对象，create 方法需要传入array。

如果其他一切都正确，这应该可以工作：

$lastid=Transaction_in::create($transaction_in->toArray())->idTransaction_in;

Answer 2

您已经拥有save 数据，但您也使用create。它将在您的数据库中创建重复记录。

我会给你一个解决方案：

$transactionIn = Transaction_in::create([
    'idTransaction_id' => '0',
    'supplier_id' => $request->input('supplier_name') // why supplier name assigned supplier_id?
    'tanggal_transaksi' => $request->input('transaction_in_date'),
]);

$transactionIn = tap($transaction_in)->update([
    'idTransaction_in' => sprintf('TIN-%04d', $transactionIn->id)
]);

$lastId = $transactionIn->idTransaction_in;