如何在不使用 Java 数组的情况下获得标准偏差？

Question

使用双浮点数据计算任何给定输入的计数、平均值和标准差。

每次我运行程序时，它都会给出我的计数和平均值，但是我的标准偏差显示为 NaN。

import java.util.Scanner;

public class Final 
{
    public static void main (String[]args)
    {
        Scanner in = new Scanner(System.in);

        System.out.print("Enter a range of digits to recieive 1. Count , 2. Average , 3. StdDvn");

        double input = in.nextDouble();

        double count = 1;
        double sum = 0;
        double sumsquared = sum * sum;
        double std = 0;

        while (in.hasNextDouble())
        { double value = in.nextDouble();

            sum = input += value;
            count++;
        }

        double average = sum / count;
        std = Math.sqrt((sumsquared-(sum/count)) / (count - 1));

        System.out.println("Your count of numbers is : " + count);
        System.out.println("Your average of numbers is : " + average);
        System.out.println("Your standard deviation of numbers is : " + std);
    }
}

Answer 1

您的sumsquaredvariable 始终为0，因为您在初始化double sum=0; 之后立即从0*0 计算它。

这部分应该移到总和之下。

同样要使用循环计算不使用数组的标准差，您需要知道以下 3 个值：

• 输入了多少个数字。
• 所有数字的总和。
• 数字的平方和。

公式：E[X^2]-(E[X])^2 见wikipedia。 ^2 当然是squared。

public static void main (String[]args)
{
    Scanner in = new Scanner(System.in);

    double count = 10.0;   // how many numbers are entered, e.g.: 10
    double sum1 = 0.0;    // sum of the numbers
    double sum2 = 0.0;    // sum of the squares
    System.out.println("Enter 10 numbers: ");
    for (int i=0; i < 10; i++) {
      double n = in.nextDouble();
      sum1 += n;
      sum2 += n * n;
    }
    double average = sum1 / count;
    double variance = (count * sum2 - sum1 * sum1) / (count * count);
    double stddev = Math.sqrt(variance);

    System.out.println("Your count of numbers is : " + count);
    System.out.println("Your average of numbers is : " + average);
    System.out.println("Your standard deviation of numbers is : " + stddev);
}

Answer 2

您的sumsquared 为零。因此，您在标准差中使用了 0 的值。这是重新定位您的 sumsquared 的修复程序。

编辑：我认为您的 std 不正确。你必须先找到平均值。在平方根内，找到 ( x - mean) 的总和，其中 x 是您的数据，然后将该结果除以 count - 1。

public static void main (String[]args)
{


    Scanner in = new Scanner(System.in);

    System.out.print("Enter a range of digits to recieive 1. Count , 2. Average , 3. StdDvn");

    double input = in.nextDouble();

    double count = 1;
    double sum = 0;
    double std = 0;

    while (in.hasNextDouble())
    { double value = in.nextDouble();

        sum = input += value;
        count++;

    }

    double sumsquared = sum * sum;
    double average = sum / count;
    std = Math.sqrt((sumsquared-(sum/count)) / (count - 1)); /* fix this formula */

    System.out.println("Your count of numbers is : " + count);
    System.out.println("Your average of numbers is : " + average);
    System.out.println("Your standard deviation of numbers is : " + std);
    }
}