printf 每个都有一个 Object 节点 #8774

Question

// Returns Testing [Object object]
describe.skip.each([[{foo: 'abc'}], [{foo: 'bca'}]])('Testing %s', ...

// Returns Testing {foo: 'abc'}
describe.skip.each([[{foo: 'abc'}], [{foo: 'bca'}]])('Testing %o', ...

有没有可能做类似...

// Expect Testing abc
describe.skip.each([[{foo: 'abc'}], [{foo: 'bca'}]])('Testing %o.foo', ...

Answer 1

我认为使用该 API 是不可能的，但使用 second API it is

describe.each`
    column
    ${{ foo: 'abc' }}
    ${{ foo: 'bca' }}
    `
    ('Testing $column.foo', ({ column }) => {
        ...
    })

更新

Sadly you cannot build a template literal programmatically, here's how tagged template literals work 需要${expresion} 来标识您要传递的数据。