如何使用 PHP 对 JSON 数据进行分类？答案

【问题标题】：How do I categorise JSON data with PHP?如何使用 PHP 对 JSON 数据进行分类？
【发布时间】：2019-02-19 11:33:18
【问题描述】：

我想按“类别”下的 ID 对我的 JSON 数据进行分类。现在我可以手动更改我想在 if 语句中显示的内容，但我希望它由实际用户完成。

我希望能够只显示类别->id = 1/2/3 的 JSON 数据。有没有一种方法可以通过按钮仅选择“一般”或“清理”博客文章？

<?php

$json_file = file_get_contents('posts.json', true);

$json = json_decode($json_file);

$posts = $json->posts;
?>

<!DOCTYPE html>
<html>
<head>
    <link rel="stylesheet" type="text/css" href="style.css">
    <title>Blog</title>
</head>

<body>

<?php
    foreach ($posts as $post) {
        if($post->categories[0]->id == "1"){
?>
    <div>
        <h2><?php echo $post->title; ?></h2>
        <p><?php echo $post->date; ?></p>
        <p><?php echo $post->content; ?></p>
        <p><?php echo $post->categories[0]->slug; ?></p>
    </div>

<?php
}}
?>

</body>
</html>

这是 JSON 数据

{
"posts": [
    {
        "title": "My Lovely Blog",
        "date": "22nd September 2018",
        "content": "Hey guys so this is my brand new blog that I will be posting on weekly! Stay tuned for more :)",
        "categories": [
            {
                "id": 1,
                "slug": "general"
            }
        ]
    },

    {
        "title": "How to clean your home fast: 10 spring cleaning tips",
        "date": "29th September 2018",
        "content": "Declutter your home: There is a simple rule you can use to declutter you home. If you have not used something...",
        "categories": [
            {
                "id": 2,
                "slug": "cleaning"
            }
        ]
    },


    {
        "title": "7 Fashion Trends to Be Thankful for This Year",
        "date": "24th November 2018",
        "content": "The trickle down effect of this trend might take a while, but on the runways, office-appropriate clothing got a serious makeover. Blazers were paired with embellished short shorts at Prada and loose, 90s-inspired trousers at Tom Ford. At Celine, daywear was rendered in sherbet colors while Michael Kors topped off plunging tops and sarong sequin skirts with wide-cut blazers and flip flops. Just because you have gone corporate does not mean you cannot have fun.",
        "categories": [
            {
                "id":3,
                "slug":"fashion"
            }
        ]
    }

] }

感谢您的帮助！！！

【问题讨论】：

标签： php html json parsing

【解决方案1】：

在不将 javascript 混合到解决方案中的情况下，您可以添加一个按钮，将您带到相同的 URL 但带有查询字符串参数：

<a href="/?filter=cleaning">Show Cleaning</a>

单击此按钮将带您进入同一页面，但您现在可以从 $_GET 全局变量中获取“过滤器”键值：

foreach ($posts as $post)
{
  if($post->categories[0]->slug == $_GET['filter'])
  {
    ...
  }
}

使用上述方法，您可以添加任意数量的按钮，以在页面上应用任意数量的过滤器。

编辑：上述解决方案假设您位于基本 URL 上，如果该页面位于 /blog/ 之类的 URL 上，则您的 href 将是 /blog/?filter=cleaning

【讨论】：