【问题标题】:How to use jQuery to paginate JSON data?如何使用 jQuery 对 JSON 数据进行分页?
【发布时间】:2011-01-31 06:13:32
【问题描述】:

重复:

Good jquery pagination plugin to use with json Data…

我的 JSON 数据如下所示

{
    "Table": [{
        "Emp_Id": "3",
        "Identity_No": "",
        "Emp_Name": "Jerome",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Supervisior",
        "Desig_Description": "Supervisior of the Construction",
        "SalaryBasis": "Monthly",
        "FixedSalary": "25000.00"
    }, {
        "Emp_Id": "4",
        "Identity_No": "",
        "Emp_Name": "Mohan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Acc ",
        "Desig_Description": "Accountant",
        "SalaryBasis": "Monthly",
        "FixedSalary": "200.00"
    }, {
        "Emp_Id": "5",
        "Identity_No": "",
        "Emp_Name": "Murugan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "150.00"
    }, {
        "Emp_Id": "6",
        "Identity_No": "",
        "Emp_Name": "Ram",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "120.00"
    }, {
        "Emp_Id": "7",
        "Identity_No": "",
        "Emp_Name": "Raja",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "135.00"
    }, {
        "Emp_Id": "8",
        "Identity_No": "",
        "Emp_Name": "Raja kumar",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason Helper",
        "Desig_Description": "Mason Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "105.00"
    }, {
        "Emp_Id": "9",
        "Identity_No": "",
        "Emp_Name": "Lakshmi",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason Helper",
        "Desig_Description": "Mason Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "100.00"
    }, {
        "Emp_Id": "10",
        "Identity_No": "",
        "Emp_Name": "Palani",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Carpenter",
        "Desig_Description": "Carpenter",
        "SalaryBasis": "Weekly",
        "FixedSalary": "200.00"
    }, {
        "Emp_Id": "11",
        "Identity_No": "",
        "Emp_Name": "Annamalai",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Carpenter",
        "Desig_Description": "Carpenter",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "12",
        "Identity_No": "",
        "Emp_Name": "David",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Fixer",
        "Desig_Description": "Steel Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "13",
        "Identity_No": "",
        "Emp_Name": "Chandru",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Fixer",
        "Desig_Description": "Steel Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "14",
        "Identity_No": "",
        "Emp_Name": "Mani",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Helper",
        "Desig_Description": "Steel Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "175.00"
    }, {
        "Emp_Id": "15",
        "Identity_No": "",
        "Emp_Name": "Karthik",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Fixer",
        "Desig_Description": "Wood Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "195.00"
    }, {
        "Emp_Id": "16",
        "Identity_No": "",
        "Emp_Name": "Bala",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Fixer",
        "Desig_Description": "Wood Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "185.00"
    }, {
        "Emp_Id": "17",
        "Identity_No": "",
        "Emp_Name": "Tamil arasi",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Helper",
        "Desig_Description": "Wood Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "185.00"
    }, {
        "Emp_Id": "18",
        "Identity_No": "",
        "Emp_Name": "Perumal",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Cook",
        "Desig_Description": "Cook",
        "SalaryBasis": "Weekly",
        "FixedSalary": "105.00"
    }, {
        "Emp_Id": "19",
        "Identity_No": "",
        "Emp_Name": "Andiappan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Watchman",
        "Desig_Description": "Watchman",
        "SalaryBasis": "Weekly",
        "FixedSalary": "150.00"
    }]
}

此 JSON 数据中有 22 条记录。如何使用 jQuery 将此 JSON 数据分页为每页 5 个?

编辑:

alt text http://img218.imageshack.us/img218/7757/fivej.jpg

上图是我使用 jQuery 迭代的员工列表的摘要视图。

var jsonObj = JSON.parse(HfJsonValue);
    for (var i = jsonObj.Table.length - 1; i >= 0; i--) {
        var employee = jsonObj.Table[i];
        $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').insertAfter('#ResultsDiv');
    }

我有 22 条记录。现在它可能会增长。如何使用 jQuery 分页对 JSON 数据进行分页?

【问题讨论】:

标签: jquery json pagination


【解决方案1】:

JQuery JSON 分页演示的简单方法https://jsfiddle.net/rijo/0kjow220/

HTML代码

<div style="width:400px">
<table class="paginated">
    <thead>
        <tr>
            <th class="col">Play Id</th>
            <th class="col">Question1</th>  
       </tr>
  </thead>
  <tbody id="myTable">
 </tbody>

</table>
<span id="nextValue">next</span><br><span id="PreeValue">Pre</span>
</div>

脚本代码

 $(document).ready(function(){
      var table =  $('#myTable');
var b = [{"play_id":"1","question1":"135","q1r":"1","question2":"138","q2r":"1","question3":"","q3r":"0","question4":"","q4r":"0","total_point":"6","amount":"1.7","bet_amount":"10","winning_amount":"20","no_of_players":"10"},....]
    var max_size=b.length;
     var sta = 0;
     var elements_per_page = 4;
     var limit = elements_per_page;
     goFun(sta,limit);
     function goFun(sta,limit) {
      for (var i =sta ; i < limit; i++) {

        var $nr = $('<tr><td>A-' + b[i]['play_id'] + '</td><td>B-' + b[i]['question1']  + '</td></tr>');
        table.append($nr);
      }
      }
      $('#nextValue').click(function(){

        var next = limit;
        if(max_size>=next) {
        limit = limit+elements_per_page;
        table.empty();
        console.log(next +' -next- '+limit);
        goFun(next,limit);
        }
      });
      $('#PreeValue').click(function(){
        var pre = limit-(2*elements_per_page);
        if(pre>=0) {
        limit = limit-elements_per_page;
        console.log(pre +' -pre- '+limit);
        table.empty();
        goFun(pre,limit); 
        }
      });

    });

【讨论】:

  • 我使用了你的代码,它非常有用。在我的项目中,我放置了上一个和下一个按钮,当没有数据时,我试图隐藏下一个按钮。如何实施,请建议我。我被困在那里。谢谢你..
【解决方案2】:

您必须更具体地说明“每页 5 个”的含义。您是否要将这些数据呈现为 HTML“页面”?

如果是这样,您需要将数据分成 5 组并进行渲染..

【讨论】:

    【解决方案3】:

    您可以使用 Array.splice 方法从数组中创建所需大小的组:

    // Parse json etc.
    var json = [...];
    // Fetch the data for a page from the json-result object
    var page = 1,
        recPerPage = 5,
        // Use Math.max to ensure that we at least start from record 0
        startRec = Math.max(page - 1, 0) * 5,
        // The end index of Array.splice doesn't have to be within boundaries,
        // But if you want to ensure that it does, then use 
        // Math.min(startRec + recPerPage, json.table.length)
        endRec = startRec + recPerPage
        recordsToShow = json.table.splice(startRec, endRec);
    

    recordsToShow 现在包含要为页面显示的记录数组。重构page = 1 并将其作为参数,对recPerPage = 5 执行相同的操作,您应该可以开始了。您可以使用 jQuery.each 遍历 recordsToShow,并使用某种模板系统从每条记录中创建 HTML 元素。

    您还应该向startRec 添加某种检查,以确保起始记录在边界内。如果不是,则显示第 1 页,或向用户显示错误消息。

    【讨论】:

      【解决方案4】:

      jQgrid 是一个很棒的 jQuery 插件,用于处理表格和分页,但是它需要非常特定格式的 json

      【讨论】:

        【解决方案5】:

        如果jsonObject是JSON对象,那么

        jsonObject.Table[0], jsonObject.Table[1], ... jsonObject.Table[4]
        

        将是第一页的对象。您将如何处理这些页面取决于您的应用程序。

        【讨论】:

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