从 HttpClient 更新为 HttpURLConnection [重复]答案

【问题标题】：updating from HttpClient to HttpURLConnection [duplicate]从 HttpClient 更新为 HttpURLConnection [重复]
【发布时间】：2015-05-23 03:58:16
【问题描述】：

我一直在开发一个 android 应用程序，最近使用 HttpClient 使所有登录代码都能正常工作。但是，此代码现已弃用，不再有效。语言摘要建议用HttpURLConnection 对象替换所有HttpClient 代码。我不知道该怎么做。如果有人可以帮助我将我的代码更改为HttpURLConnection 以提交登录表单并检索信息，将不胜感激。这是我原来的使用功能代码：

String u = params[0];
String p = params[1];
DefaultHttpClient client = new DefaultHttpClient();
client.getParams().setParameter(ClientPNames.HANDLE_REDIRECTS,Boolean.TRUE);
//client.setRedirectStrategy(new LaxRedirectStrategy());
HttpPost post = new HttpPost("https://home-access.cfisd.net/HomeAccess/Account/LogOn");
List<NameValuePair> list = new ArrayList<NameValuePair>();
list.add(new BasicNameValuePair("LogOnDetails.Username", u));
list.add(new BasicNameValuePair("LogOnDetails.Password",p));
list.add(new BasicNameValuePair("Database","10"));
HttpResponse response = null;
try{
    post.setEntity(new UrlEncodedFormEntity(list));
    response = client.execute(post);
}
catch(Exception ex)
{
    ex.printStackTrace();
}

【问题讨论】：

看看这个问题的答案stackoverflow.com/questions/4205980/…
您可以参考这篇文章使用 HttpUrlConnection 转换您的代码。 mkyong.com/java/how-to-send-http-request-getpost-in-java
我尝试研究所有这些想法，但它们都没有让我明白。它们都以响应代码 200 终止，但登录后都不会继续到下一页。还有什么我需要做的或者我缺少的吗？
stackoverflow.com/questions/1739548/… stackoverflow.com/questions/8534342/… stackoverflow.com/questions/8534342/…

标签： java android forms httpclient httpurlconnection

【解决方案1】：

嘿兄弟，得到一个像

这样的图书馆

androids 的默认设置既旧又笨重

loopjs asynchttpclient 或 okhttp 或 Koushs ion

你用 2-3 行代码做了很多工作

loopjs 异步 http 示例

RequestParams params = new RequestParams();
params.put("key", "value");
params.put("more", "data");
AsyncHttpClient client = new AsyncHttpClient();
client.post(url, params, responseHandler);

//do something with response
@Override
        public void onSuccess(int statusCode, Header[] headers, JSONObject response) {

        }

        @Override
        public void onSuccess(int statusCode, Header[] headers, JSONArray response) {

        }
    });

【讨论】：

【解决方案2】：

您可以获取连接的输出流并将参数查询字符串写入其中。

URL url = new URL("http://yoururl.com");
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();

conn.setReadTimeout(10000);

conn.setConnectTimeout(15000);

conn.setRequestMethod("POST");

conn.setDoInput(true);

conn.setDoOutput(true);

List<NameValuePair> params = new ArrayList<NameValuePair>();

params.add(new BasicNameValuePair("firstParam", paramValue1));

params.add(new BasicNameValuePair("secondParam", paramValue2));

params.add(new BasicNameValuePair("thirdParam", paramValue3));

OutputStream os = conn.getOutputStream();

BufferedWriter writer = new BufferedWriter(
        new OutputStreamWriter(os, "UTF-8"));

writer.write(getQuery(params));

writer.flush();

writer.close();

os.close();

conn.connect();

....

private String getQuery(List<NameValuePair> params) throws UnsupportedEncodingException
{

    StringBuilder result = new StringBuilder();
boolean first = true;

for (NameValuePair pair : params)
{
    if (first)
        first = false;
    else
        result.append("&");

    result.append(URLEncoder.encode(pair.getName(), "UTF-8"));
    result.append("=");
    result.append(URLEncoder.encode(pair.getValue(), "UTF-8"));
}

return result.toString();
}

【讨论】：